使用子类 FuncAnimation 的动画播放器时出现播放错误
Playback error results when using an animation player that subclasses FuncAnimation
Python3.9,MacOS11.6.1
我正在实现几年前在 上发布的动画示例,其中包含一个不错的播放控制台。然而,当动画结束时,再次按下播放按钮将抛出越界索引错误。我如何修改代码,为了完整起见,我在下面包含了这些代码,以便在动画结束时按下播放按钮时什么也不会发生,或者更好的是,动画从头开始。
import matplotlib.pyplot as plt
from matplotlib.animation import FuncAnimation
import mpl_toolkits.axes_grid1
import matplotlib.widgets
class Player(FuncAnimation):
def __init__(self, fig, func, frames=None, init_func=None, fargs=None,
save_count=None, mini=0, maxi=100, pos=(0.125, 0.92), **kwargs):
self.i = 0
self.min=mini
self.max=maxi
self.runs = True
self.forwards = True
self.fig = fig
self.func = func
self.setup(pos)
FuncAnimation.__init__(self,self.fig, self.func, frames=self.play(),
init_func=init_func, fargs=fargs,
save_count=save_count, **kwargs )
def play(self):
while self.runs:
self.i = self.i+self.forwards-(not self.forwards)
if self.i > self.min and self.i < self.max:
yield self.i
else:
self.stop()
yield self.i
def start(self):
self.runs=True
self.event_source.start()
def stop(self, event=None):
self.runs = False
self.event_source.stop()
def forward(self, event=None):
self.forwards = True
self.start()
def backward(self, event=None):
self.forwards = False
self.start()
def oneforward(self, event=None):
self.forwards = True
self.onestep()
def onebackward(self, event=None):
self.forwards = False
self.onestep()
def onestep(self):
if self.i > self.min and self.i < self.max:
self.i = self.i+self.forwards-(not self.forwards)
elif self.i == self.min and self.forwards:
self.i+=1
elif self.i == self.max and not self.forwards:
self.i-=1
self.func(self.i)
self.fig.canvas.draw_idle()
def setup(self, pos):
playerax = self.fig.add_axes([pos[0],pos[1], 0.22, 0.04])
divider = mpl_toolkits.axes_grid1.make_axes_locatable(playerax)
bax = divider.append_axes("right", size="80%", pad=0.05)
sax = divider.append_axes("right", size="80%", pad=0.05)
fax = divider.append_axes("right", size="80%", pad=0.05)
ofax = divider.append_axes("right", size="100%", pad=0.05)
self.button_oneback = matplotlib.widgets.Button(playerax, label=u'$\u29CF$')
self.button_back = matplotlib.widgets.Button(bax, label=u'$\u25C0$')
self.button_stop = matplotlib.widgets.Button(sax, label=u'$\u25A0$')
self.button_forward = matplotlib.widgets.Button(fax, label=u'$\u25B6$')
self.button_oneforward = matplotlib.widgets.Button(ofax, label=u'$\u29D0$')
self.button_oneback.on_clicked(self.onebackward)
self.button_back.on_clicked(self.backward)
self.button_stop.on_clicked(self.stop)
self.button_forward.on_clicked(self.forward)
self.button_oneforward.on_clicked(self.oneforward)
### using this class is as easy as using FuncAnimation:
fig, ax = plt.subplots()
x = np.linspace(0,6*np.pi, num=100)
y = np.sin(x)
ax.plot(x,y)
point, = ax.plot([],[], marker="o", color="crimson", ms=15)
def update(i):
point.set_data(x[i],y[i])
ani = Player(fig, update, maxi=len(y)-1)
plt.show()
一种方法是在 start
函数中添加 if
条件,以检查 self.i
值是否达到 self.max
。如果是这样,您可以将 self.i
值重置为零,然后让动画重新开始。下面是执行此操作的代码:
def start(self):
if self.i==self.max:
self.i=0
self.runs=True
self.event_source.start()
Python3.9,MacOS11.6.1
我正在实现几年前在
import matplotlib.pyplot as plt
from matplotlib.animation import FuncAnimation
import mpl_toolkits.axes_grid1
import matplotlib.widgets
class Player(FuncAnimation):
def __init__(self, fig, func, frames=None, init_func=None, fargs=None,
save_count=None, mini=0, maxi=100, pos=(0.125, 0.92), **kwargs):
self.i = 0
self.min=mini
self.max=maxi
self.runs = True
self.forwards = True
self.fig = fig
self.func = func
self.setup(pos)
FuncAnimation.__init__(self,self.fig, self.func, frames=self.play(),
init_func=init_func, fargs=fargs,
save_count=save_count, **kwargs )
def play(self):
while self.runs:
self.i = self.i+self.forwards-(not self.forwards)
if self.i > self.min and self.i < self.max:
yield self.i
else:
self.stop()
yield self.i
def start(self):
self.runs=True
self.event_source.start()
def stop(self, event=None):
self.runs = False
self.event_source.stop()
def forward(self, event=None):
self.forwards = True
self.start()
def backward(self, event=None):
self.forwards = False
self.start()
def oneforward(self, event=None):
self.forwards = True
self.onestep()
def onebackward(self, event=None):
self.forwards = False
self.onestep()
def onestep(self):
if self.i > self.min and self.i < self.max:
self.i = self.i+self.forwards-(not self.forwards)
elif self.i == self.min and self.forwards:
self.i+=1
elif self.i == self.max and not self.forwards:
self.i-=1
self.func(self.i)
self.fig.canvas.draw_idle()
def setup(self, pos):
playerax = self.fig.add_axes([pos[0],pos[1], 0.22, 0.04])
divider = mpl_toolkits.axes_grid1.make_axes_locatable(playerax)
bax = divider.append_axes("right", size="80%", pad=0.05)
sax = divider.append_axes("right", size="80%", pad=0.05)
fax = divider.append_axes("right", size="80%", pad=0.05)
ofax = divider.append_axes("right", size="100%", pad=0.05)
self.button_oneback = matplotlib.widgets.Button(playerax, label=u'$\u29CF$')
self.button_back = matplotlib.widgets.Button(bax, label=u'$\u25C0$')
self.button_stop = matplotlib.widgets.Button(sax, label=u'$\u25A0$')
self.button_forward = matplotlib.widgets.Button(fax, label=u'$\u25B6$')
self.button_oneforward = matplotlib.widgets.Button(ofax, label=u'$\u29D0$')
self.button_oneback.on_clicked(self.onebackward)
self.button_back.on_clicked(self.backward)
self.button_stop.on_clicked(self.stop)
self.button_forward.on_clicked(self.forward)
self.button_oneforward.on_clicked(self.oneforward)
### using this class is as easy as using FuncAnimation:
fig, ax = plt.subplots()
x = np.linspace(0,6*np.pi, num=100)
y = np.sin(x)
ax.plot(x,y)
point, = ax.plot([],[], marker="o", color="crimson", ms=15)
def update(i):
point.set_data(x[i],y[i])
ani = Player(fig, update, maxi=len(y)-1)
plt.show()
一种方法是在 start
函数中添加 if
条件,以检查 self.i
值是否达到 self.max
。如果是这样,您可以将 self.i
值重置为零,然后让动画重新开始。下面是执行此操作的代码:
def start(self):
if self.i==self.max:
self.i=0
self.runs=True
self.event_source.start()