如何在 python 中的休息请求查询中传递日期参数：sysparm_query

Question

按日期过滤休息请求的最佳方法是什么？

可能会像这样传递一个变量：

today = date.today() today_90 = today - timedelta(days = 90)

service-now.com/api/now/table/incident?sysparm_limit=1000&sysparm_query=sys_created_on**dates values here?**

Answer 1

我试着理解你的问题：

from datetime import date, timedelta
import requests

today = date.today() 
today_90 = today - timedelta(days = 90)


r = requests.get('https://xxxx.service-now.com/api/now/table/incident?sysparm_limit=1000&sysparm_query=sys_created_on>' + str(today_90) + '&sysparm_query=sys_created_on<' + str(today))

如何在 python 中的休息请求查询中传递日期参数：sysparm_query

how to pass date parameter in a rest request query in python: sysparm_query

python

rest

web