如何在 EF 中使用强类型 ID？

Question

我有原始的痴迷 class EmailAddress 已经覆盖 ToString():

public class EmailAddress
{
   private string _value;

   public EmailAddress(string value)
   {
        _value = value;
   }

   public override string ToString()
   {
        return _value;
   }
}

我的域模型 Customer 看起来像：

public class Customer
{
   public EmailAddress EmailAddress { get; set; }
   public string FullName{ get; set; } 
}

并且我在 FluentApi 中为 EmailAddress 配置了转换：

modelBuilder.Entity<Customer>().Property(x => x.EmailAddress)
                .HasConversion(
                x => x.ToString(),
                x => new EmailAddress(x));

我还有通用存储库模式，当我想过滤数据时：

public List<Customer> GetCustomers(GetCustomersQuery queryParameters)
{

  IQueryable<Customer> queryCustomers = _customerContext.GetAll();

  return queryCustomers.Where(x =>
         x.EmailAddress.ToString()
        .Contains(queryParameters.Email)).ToList();
}

我有一个错误：

The LINQ expression DbSet<Customer>().Where(t => t.EmailAddress.ToString() could not be translated. Additional information: Translation of method object.ToString failed.

我试过 EF 6.4 你有什么解决方法吗？

Answer 1

真正上进，不怕复杂的领域，我找到了解决方案

public class EmailAddress
{
   private string _value;

   public static explicit operator string(EmailAddress emailAddress) => emailAddress._value;

   public EmailAddress(string value)
   {
        _value = value;
   }

   public override string ToString()
   {
        return _value;
   }
}

查询是

queryCustomers.Where(x =>
         ((string)x.EmailAddress)
        .Contains(queryParameters.Email)).ToList();

此查询正在服务器端执行。

如何在 EF 中使用强类型 ID？

How to use strongly typed id in in EF?

.net

c#

entity-framework