如何删除一些额外的元组和列表并在 python 中的字符串之间打印一些额外的东西?

How to remove some extra tuples and lists and print some extra stuff between the strings in python?

 bounds = reader.readtext(np.array(images[0]), min_size=0,slope_ths=0.2, ycenter_ths=0.7, height_ths=0.6,width_ths=0.8,decoder='beamsearch',beamWidth=10) 
 print(bounds)

以上代码的输出是

我有一个像

这样的字符串格式
[([[1004, 128], [1209, 128], [1209, 200], [1004, 200]],
  'EC~L',
  0.18826377391815186),
 ([[177, 179], [349, 179], [349, 241], [177, 241]], 'OKI', 0.9966741294455473),
 ([[180, 236], [422, 236], [422, 268], [180, 268]],
  'Oki Eleclric Industry Co',
  0.8091106257361781),
 ([[435, 243], [469, 243], [469, 263], [435, 263]], 'Ltd', 0.9978489622393302),
 ([[180, 265], [668, 265], [668, 293], [180, 293]],
  '4-11-22 , Shibaura, Minalo-ku, Tokyo 108-855| Japan',
  0.6109240973537998),
 ([[180, 291], [380, 291], [380, 318], [180, 318]],
  'Tel +81-3-5440-4884',
  0.9406430290171053)]

如何编写 python 代码来打印类似于以下格式的上述格式:

[1004, 128, 1209, 128, 1209, 200, 1004, 200], 
'EC~L'
##################
[177, 179, 349, 179, 349, 241, 177, 241],
'OKI'
##################
[180, 236, 422, 236, 422, 268, 180, 268],
'Oki Eleclric Industry Co'
##################
[435, 243, 469, 243, 469, 263, 435, 263], 
'Ltd'
##################
[180, 265, 668, 265, 668, 293, 180, 293],
'4-11-22 , Shibaura, Minalo-ku, Tokyo 108-855| Japan'
##################
[180, 291, 380, 291, 380, 318, 180, 318],
'Tel +81-3-5440-4884'

谁能帮我解决这个问题?

如果我没理解错的话:

for l, s, _ in bounds:
    print([lll for ll in l for lll in ll])
    print(s)
    print('##################')

输出:

[1004, 128, 1209, 128, 1209, 200, 1004, 200]
EC~L
##################
[177, 179, 349, 179, 349, 241, 177, 241]
OKI
##################
[180, 236, 422, 236, 422, 268, 180, 268]
Oki Eleclric Industry Co
##################
[435, 243, 469, 243, 469, 263, 435, 263]
Ltd
##################
[180, 265, 668, 265, 668, 293, 180, 293]
4-11-22 , Shibaura, Minalo-ku, Tokyo 108-855| Japan
##################
[180, 291, 380, 291, 380, 318, 180, 318]
Tel +81-3-5440-4884
##################

我想我会为这个单行解决方案做出贡献。

print("\n##################\n".join(("{},\n'{}'".format([x for item in items[0] for x in item], items[1])) for items in bounds))

生成的格式与提问者的期望完全相同:

[1004, 128, 1209, 128, 1209, 200, 1004, 200],
'EC~L'
##################
[177, 179, 349, 179, 349, 241, 177, 241],
'OKI'
##################
[180, 236, 422, 236, 422, 268, 180, 268],
'Oki Eleclric Industry Co'
##################
[435, 243, 469, 243, 469, 263, 435, 263],
'Ltd'
##################
[180, 265, 668, 265, 668, 293, 180, 293],
'4-11-22 , Shibaura, Minalo-ku, Tokyo 108-855| Japan'
##################
[180, 291, 380, 291, 380, 318, 180, 318],
'Tel +81-3-5440-4884'

另一个解决方案

from itertools import chain

for numbers, description, _ in bounds:
    numbers = list(chain(*numbers))
    print(f"{numbers},\n"
          f"'{description}'\n"
          "##################")

输出:

[1004, 128, 1209, 128, 1209, 200, 1004, 200],
'EC~L'
##################
[177, 179, 349, 179, 349, 241, 177, 241],
'OKI'
##################
[180, 236, 422, 236, 422, 268, 180, 268],
'Oki Eleclric Industry Co'
##################
[435, 243, 469, 243, 469, 263, 435, 263],
'Ltd'
##################
[180, 265, 668, 265, 668, 293, 180, 293],
'4-11-22 , Shibaura, Minalo-ku, Tokyo 108-855| Japan'
##################
[180, 291, 380, 291, 380, 318, 180, 318],
'Tel +81-3-5440-4884'
##################