PHP

Question

我只是简化了我拥有的 JSON 数据，因为我只需要其中的两个值。正如您在下面的代码中看到的那样，我过滤了我需要的内容，但在某些值中为 0 并且在输出时只有零需要作为新值 'Free'.

这是我现在得到的代码：

    $json = '[{"Number":"333567","Cost":0},{"Number":"333568","Cost":7500},{"Number":"333569","Cost":7500}]';
    $options = json_decode($json, true);

        $newArray = [];
        foreach ($options as $key => $value) {
            $newArray[$value['Number']]= $value['Number']." "."&pound;".$value['Cost'] / 100;
        }
    echo '<br>';
    echo '<br>';

    print_r($newArray);

我得到的结果是：

Array ( [333567] => 333567 £0 [333568] => 333568 £75 [333569] => 333569 £75 )

但我只需要输出 £0 是免费像这样:

Array ( [333567] => 333567 Free [333568] => 333568 £75 [333569] => 333569 £75 )

Answer 1

如果我对问题的理解正确，你会想要替换

        $newArray[$value['Number']]= $value['Number']." "."&pound;".$value['Cost'] / 100;

和

        $priceLabel = ($value['Number'] == 0 ? 'Free' : $value['Number'] . " &pound;");
        $newArray[( $value['Number'] )] = $priceLabel . ($value['Cost'] / 100);

Answer 2

你可以试试 $value['Cost'] / 100 > 0 ? $值['Cost'] : 'free' 您的代码如下

    $json = '[{"Number":"333567","Cost":0},{"Number":"333568","Cost":7500},{"Number":"333569","Cost":7500}]';
    $options = json_decode($json, true);

        $newArray = [];
        foreach ($options as $key => $value) {
            $newArray[$value['Number']]= $value['Number']." "."&pound;".($value['Cost'] / 100 > 0 ? $value['Cost'] : 'free');
        }
    echo '<br>';
    echo '<br>';

    print_r($newArray);

Answer 3

$newArray[$value['Number']]= $value['Number']." ".($value['Cost'] / 100 == 0 ? 'Free': "&pound;".$value['Cost'] / 100);

希望能解决你的问题

PHP - 仅将带有“0”的值更改为字符串 'Free'

PHP - Change only value with '0' to string 'Free'

arrays

foreach

json

replace