如何根据 json 中嵌套的条件过滤复杂的 json？

Question

我有一个复杂对象数组，需要根据多个条件进行过滤

var myList= [
  {
    "UserId": 1,
    "UserDetails": {
      "Department": [
        {
          "Name": "dept1"
        }
      ],
      "Projects": [
        {
          "Name": "Project1"
        },
        {
          "Name": "Project2"
        }
      ]
    }
  },
  {
    "UserId": 2,
    "UserDetails": {
      "Department": [
        {
          "Name": "dept2"
        }
      ],
      "Projects": [
        {
          "Name": "Project3"
        },
        {
          "Name": "Project4"
        }
      ]
    }
  },
  {
    "UserId": 3,
    "UserDetails": {
      "Department": [
        {
          "Name": "dept3"
        }
      ],
      "Projects": [
        {
          "Name": "Project5"
        },
        {
          "Name": "Project6"
        }
      ]
    }
  }
]

我想在两个条件下进行过滤：Department-->Name 是“dept3”，或者存在一个名称为“Project3”的项目

var filteredElements=this.myList.filter((x)=>x.UserDetails.filter((y)=>y.Department... ??

如何编写代码来过滤这两个条件？

Answer 1

您不能在 UserDetails 上使用过滤器，因为它不是数组而是对象。

在 Department 和 Projects 上应用 find，并在满足要求的条件下在它们之间应用 OR 条件。

var myList= [
    {
      "UserId": 1,
      "UserDetails": {
        "Department": [
          {
            "Name": "dept1"
          }
        ],
        "Projects": [
          {
            "Name": "Project1"
          },
          {
            "Name": "Project2"
          }
        ]
      }
    },
    {
      "UserId": 2,
      "UserDetails": {
        "Department": [
          {
            "Name": "dept2"
          }
        ],
        "Projects": [
          {
            "Name": "Project3"
          },
          {
            "Name": "Project4"
          }
        ]
      }
    },
    {
      "UserId": 3,
      "UserDetails": {
        "Department": [
          {
            "Name": "dept3"
          }
        ],
        "Projects": [
          {
            "Name": "Project5"
          },
          {
            "Name": "Project6"
          }
        ]
      }
    }
  ]
  
var filteredElements = myList.filter(x =>x.UserDetails.Department.find(d => d.Name == "dept3") || x.UserDetails.Projects.find(p => p.Name == "Project3"))
console.log(filteredElements)

Answer 2

满足条件

用户属于部门“dept3”

user.UserDetails.Department.some(department => department.Name == "dept3")
有一个名为“Project3”的项目

user.UserDetails.Projects.some(project => project.Name == "Project3")

现在将它链接在一起，

var filteredElements = this.myList.filter(user => 
    user.UserDetails.Department.some(department => department.Name == "dept3") || 
    user.UserDetails.Projects.some(project => project.Name == "Project3"))

Answer 3

myList.filter(i => i.UserDetails.Department.some(d => d.Name === 'dept3') || i.UserDetails.Projects.some(p => p.Name === 'Project3'))

如何根据 json 中嵌套的条件过滤复杂的 json？

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