SwiftUI 按作业层次结构排序列表
SwiftUI sort list by job hierarchy
我正在尝试按作业层次结构对我的数组进行排序。
例如我有模型:
struct Employee{
let name: String
let job: String
let phone: String
let mail: Sting
}
然后我有员工
class EmployeeViewModel: ObservableObject{
@Published var employees: [Employee] = [
Employee(name: "John", job: "Manager", age: 32),
Employee(name: "Anna", job: "CEO", age: 40),
Employee(name: "Julia", job: "Junior Developer", age: 25),
Employee(name: "Kevin", job: "Senior Developer", age: 29)
]
}
我想将它们排序到这样的列表中:
CEO Anna
Manager John
Kevin Senior Developer
Julia Junior Developer
有什么简单的方法吗?
您的 Employee
结构和您的 EmployeeViewModel.employees
不匹配,所以我更改了 Employee
以符合要求。为了使其可排序,Employee
必须符合 Comparable
协议。由于您想要一个固定的工作顺序,最简单的方法是使用 enum
对它们进行排名。此外,Employee
应符合 Identifiable
协议,以便在 ForEach
中使用它们用于显示目的。你可以稍微作弊,但最终你还是要顺从,所以从一开始就养成习惯。
struct SortByJob: View {
@StateObject var employeeVM = EmployeeViewModel()
var body: some View {
List {
ForEach(employeeVM.employees.sorted()) { employee in
HStack(spacing: 5) {
Text(employee.job.description)
Text(employee.name)
}
}
}
}
}
struct Employee: Identifiable, Comparable {
let id = UUID()
let name: String
let job: Job
let age: Int
static func < (lhs: Employee, rhs: Employee) -> Bool {
lhs.job.rawValue < rhs.job.rawValue
}
}
enum Job: Int {
case ceo = 1
case manager = 2
case seniorDeveloper = 3
case juniorDeveloper = 4
// This allows you to return a String from the enum for display purposes.
var description: String {
switch self {
case .ceo:
return "CEO"
case .manager:
return "Manager"
case .seniorDeveloper:
return "Senior Developer"
case .juniorDeveloper:
return "Junior Developer"
}
}
}
我正在尝试按作业层次结构对我的数组进行排序。
例如我有模型:
struct Employee{
let name: String
let job: String
let phone: String
let mail: Sting
}
然后我有员工
class EmployeeViewModel: ObservableObject{
@Published var employees: [Employee] = [
Employee(name: "John", job: "Manager", age: 32),
Employee(name: "Anna", job: "CEO", age: 40),
Employee(name: "Julia", job: "Junior Developer", age: 25),
Employee(name: "Kevin", job: "Senior Developer", age: 29)
]
}
我想将它们排序到这样的列表中:
CEO Anna
Manager John
Kevin Senior Developer
Julia Junior Developer
有什么简单的方法吗?
您的 Employee
结构和您的 EmployeeViewModel.employees
不匹配,所以我更改了 Employee
以符合要求。为了使其可排序,Employee
必须符合 Comparable
协议。由于您想要一个固定的工作顺序,最简单的方法是使用 enum
对它们进行排名。此外,Employee
应符合 Identifiable
协议,以便在 ForEach
中使用它们用于显示目的。你可以稍微作弊,但最终你还是要顺从,所以从一开始就养成习惯。
struct SortByJob: View {
@StateObject var employeeVM = EmployeeViewModel()
var body: some View {
List {
ForEach(employeeVM.employees.sorted()) { employee in
HStack(spacing: 5) {
Text(employee.job.description)
Text(employee.name)
}
}
}
}
}
struct Employee: Identifiable, Comparable {
let id = UUID()
let name: String
let job: Job
let age: Int
static func < (lhs: Employee, rhs: Employee) -> Bool {
lhs.job.rawValue < rhs.job.rawValue
}
}
enum Job: Int {
case ceo = 1
case manager = 2
case seniorDeveloper = 3
case juniorDeveloper = 4
// This allows you to return a String from the enum for display purposes.
var description: String {
switch self {
case .ceo:
return "CEO"
case .manager:
return "Manager"
case .seniorDeveloper:
return "Senior Developer"
case .juniorDeveloper:
return "Junior Developer"
}
}
}