Pygame中的贪吃蛇游戏，如何让苹果原地不动

Question

我是使用 pygame 和 python 本身的初学者。我正在制作蛇游戏，但我不知道如何让苹果留在同一个地方。到目前为止，我制作了一个游戏板并开始了蛇。苹果正在产卵，但问题是它每秒都在改变它的位置，我不知道如何阻止它

到目前为止，这是我的代码：

 import pygame
 import sys
 import random

 pygame.init()

 SPAWNSNAKE = pygame.USEREVENT          #events
 pygame.time.set_timer(SPAWNSNAKE, 800)

 WHITE = (150, 150, 150)
 RED = (255, 0, 0)
 GREEN = (30, 50, 30) #colors
 BLACK = (0, 0, 0)

 FPS = 1
 WIDTH = 500
 HEIGHT = 500

 DISPLAY = pygame.display.set_mode((WIDTH, HEIGHT))
 DISPLAY.fill(GREEN)

 grid_size = 25

 snake_list = []
 apple_list = []
 grid_list = []


class Snake: #creates a starting snake

   def __init__(self):
       self.snake = [(0, 475), (25, 475), (50, 475), (75, 475), (100, 475)]
       self.snake_width = grid_size
       self.snake_height = grid_size

   def create_snake(self):
       for x, y in self.snake:
       snake_rect = pygame.Rect(x, y, self.snake_width, self.snake_height)
       snake_list.append(snake_rect)

   def draw_snake(self):
       for rectangle in snake_list:
       pygame.draw.rect(DISPLAY, BLACK, rectangle)


   def draw_grid(): #draws game board
       for x in range(0, WIDTH, grid_size):
           for y in range(0, HEIGHT, grid_size):
               rect = pygame.Rect(x, y, grid_size, grid_size)
               pygame.draw.rect(DISPLAY, WHITE, rect, 1)
               grid_list.append(rect)


class Apples:
    def create_apple(self): #creates an apple and adds it to the list
        apple = random.choice(grid_list)
        apple_list.append(apple)

    def draw_apple(self): #draws that apple on screen
        for apple_rectangle in apple_list:
            pygame.draw.rect(DISPLAY, RED, apple_rectangle)


snake = Snake()
apples = Apples()

clock = pygame.time.Clock()

while True:
    draw_grid()
    clock.tick(FPS)
    for event in pygame.event.get():
         if event.type == pygame.QUIT:
             pygame.quit()
             sys.exit()
         if event.type == SPAWNSNAKE:
             snake.create_snake()
         if len(apple_list) == 1: #always keeps apple count 1
             apple_list = apple_list[1:]
             DISPLAY.fill(GREEN)  #refreshes display so that previous apples dissapears(works so far but that 1 apple changes it's place every second)
             draw_grid()

print(apple_list)
apples.create_apple()
snake.draw_snake()
apples.draw_apple()
pygame.display.update()

我该怎么做才能让苹果总是在同一个地方？

Answer 1

了解 Classes and Instance Objects。不要创造 class 个苹果。为苹果创建 class。您可以从这个实例中创建任意数量的实例 class:

class Apple:
    def __init__(self):
        self.rect = random.choice(grid_list)
    def draw(self):
        pygame.draw.rect(DISPLAY, RED, self.rect)

创建苹果并将它们添加到应用程序循环之前的苹果列表中。在应用程序循环中绘制列表中的苹果：

apple_list = []
apple1 = Apple()
apple_list.append(apple1)
apple2 = Apple()
apple_list.append(apple2)

# [...]

while True:
    # [...]

    for apple in apple_list:
        apple.draw()

    # [...]

Pygame中的贪吃蛇游戏，如何让苹果原地不动

Snake game in Pygame, how to make apple stay in the same place

python

pygame