如何将请求结果的响应插入到 tkinter python 上的列表框中？

Question

我的代码有问题，如何将请求结果的响应插入或输入到列表框中，结果能否放在列表框的中间，我是 tkinter 的新手，这是代码：

from tkinter import *
from tkinter import messagebox
import requests

root = Tk()
root.configure(bg="black")
root.geometry('500x450')
root.resizable(0,0)
root.title("Cek Url")

c1 = "#00ee00"
c2 = "#222222"
c3 = "#111111"

root.tk_setPalette(background=c2,foreground=c1,activeBackground=c3,activeForeground=c2,highlightColor=c1,highlightBackground=c1)

Label(root,text = 'CHECK URL',bg="black", fg ="cyan", font ='aerial 20 bold').place(x=180, y=35)
link = StringVar()
link_enter = Entry(root, width = 70,textvariable = link).place(x = 32, y = 100)

def ms():
    messagebox.showinfo("About","Simple URL Check")

def main():
    request = "https://unshorten.me/raw/" + link.get()
    response = requests.get(request).text
    print(response)

frame = Frame(root)
frame.place(width="370", height="215",x="60", y="133")
listbox = Listbox(frame, width="59",height="6")
scrollbar = Scrollbar(frame)
scrollbar.pack(side=RIGHT, fill=Y)
listbox.config(yscrollcommand=scrollbar.set)
scrollbar.config(command=listbox.yview)

Button(root,text = 'Check Url', font = 'aerial 15 bold' ,bg = 'cyan', padx = 2, fg="black", command=main).place(x=203 ,y = 375)
Button(root,text = 'About', font = 'aerial 15 bold' ,bg = 'cyan', padx = 2, fg="black", command=ms).place(x=25 ,y = 375)

root.mainloop()

Answer 1

您忘记将列表框放入框架中。插入后会显示文字。

那你就可以用评论者说的listbox.insert('end', response)了。您还可以使该功能删除最后一个回复。

你可以找到很多你想知道的关于列表框的信息here。

由您决定如何格式化 text/output。 :)

from tkinter import *
from tkinter import messagebox
import requests

root = Tk()
root.configure(bg="black")
root.geometry('500x450')
root.resizable(0,0)
root.title("Cek Url")

c1 = "#00ee00"
c2 = "#222222"
c3 = "#111111"

root.tk_setPalette(background=c2,foreground=c1,activeBackground=c3,activeForeground=c2,highlightColor=c1,highlightBackground=c1)

Label(root,text = 'CHECK URL',bg="black", fg ="cyan", font ='aerial 20 bold').place(x=180, y=35)
link = StringVar()
link_enter = Entry(root, width = 70,textvariable = link).place(x = 32, y = 100)

def ms():
    messagebox.showinfo("About","Simple URL Check")

def main():
    request = "https://unshorten.me/raw/" + link.get()
    response = requests.get(request).text
    listbox.insert(END, response)  #Changed!
    print(response)


frame = Frame(root)
frame.place(width="370", height="215",x="60", y="133")
listbox = Listbox(frame, width="59",height="6")
listbox.pack() #Changed!
scrollbar = Scrollbar(frame)
scrollbar.pack(side=RIGHT, fill=Y)
listbox.config(yscrollcommand=scrollbar.set)
scrollbar.config(command=listbox.yview)


Button(root,text = 'Check Url', font = 'aerial 15 bold' ,bg = 'cyan', padx = 2, fg="black", command=main).place(x=203 ,y = 375)
Button(root,text = 'About', font = 'aerial 15 bold' ,bg = 'cyan', padx = 2, fg="black", command=ms).place(x=25 ,y = 375)

root.mainloop()

如何将请求结果的响应插入到 tkinter python 上的列表框中？

how do I insert the response from requests results into the listbox on tkinter python?

python

tkinter

python-requests