KeyError:'1,2' running Postgresql regexp_match() in Jupyter Notebook

Question

我正在使用 Jupyter notebook 运行 postgresql。 Python、postgres、pips 和 Jupyter 都是最新的。我已经能够加载 sql 和

%load_ext sql

并使用

连接到 postgres 数据库

%sqlpostgresql://postgres:postgres@localhost/analysis

Table 已创建并加载了一个用

成功加载的 csv

%%sql
CREATE TABLE crime_reports (
 crime_id bigserial PRIMARY KEY,
 date_1 timestamp with time zone,
 date_2 timestamp with time zone,
 street varchar(250),
 city varchar(100),
 crime_type varchar(100),
 description text,
 case_number varchar(50),
 original_text text NOT NULL
);
COPY crime_reports (original_text)
FROM 'C:\YourDirectory\crime_reports.csv'
WITH (FORMAT CSV, HEADER OFF, QUOTE '"');

但是，这段代码

%%sql
SELECT crime_id,
 regexp_match(original_text, '\d{1,2}\/\d{1,2}\/\d{2}')
FROM crime_reports;

运行s 在 pgAdmin 中成功 ，返回日期 but Jupyter 笔记本我得到这个错误：


KeyError                                  Traceback (most recent call last)
~\AppData\Local\Temp/ipykernel_10976/608277809.py in <module>
----> 1 get_ipython().run_cell_magic('sql', '', "SELECT crime_id,\n regexp_match(original_text, '\d{1,2}\/\d{1,2}\/\d{2}')\nFROM crime_reports;\n")

~\AppData\Local\Programs\Python\Python310\lib\site-packages\IPython\core\interactiveshell.py in run_cell_magic(self, magic_name, line, cell)
   2417             with self.builtin_trap:
   2418                 args = (magic_arg_s, cell)
-> 2419                 result = fn(*args, **kwargs)
   2420             return result
   2421 

~\AppData\Local\Programs\Python\Python310\lib\site-packages\decorator.py in fun(*args, **kw)
    230             if not kwsyntax:
    231                 args, kw = fix(args, kw, sig)
--> 232             return caller(func, *(extras + args), **kw)
    233     fun.__name__ = func.__name__
    234     fun.__doc__ = func.__doc__

~\AppData\Local\Programs\Python\Python310\lib\site-packages\IPython\core\magic.py in <lambda>(f, *a, **k)
    185     # but it's overkill for just that one bit of state.
    186     def magic_deco(arg):
--> 187         call = lambda f, *a, **k: f(*a, **k)
    188 
    189         if callable(arg):

~\AppData\Local\Programs\Python\Python310\lib\site-packages\decorator.py in fun(*args, **kw)
    230             if not kwsyntax:
    231                 args, kw = fix(args, kw, sig)
--> 232             return caller(func, *(extras + args), **kw)
    233     fun.__name__ = func.__name__
    234     fun.__doc__ = func.__doc__

~\AppData\Local\Programs\Python\Python310\lib\site-packages\IPython\core\magic.py in <lambda>(f, *a, **k)
    185     # but it's overkill for just that one bit of state.
    186     def magic_deco(arg):
--> 187         call = lambda f, *a, **k: f(*a, **k)
    188 
    189         if callable(arg):

~\AppData\Local\Programs\Python\Python310\lib\site-packages\sql\magic.py in execute(self, line, cell, local_ns)
    149         cell_params = {}
    150         for variable in cell_variables:
--> 151             cell_params[variable] = local_ns[variable]
    152         cell = cell.format(**cell_params)
    153 

KeyError: '1,2'

我已尝试信任笔记本，但仍然遇到同样的错误。

Answer 1

尝试替换这个：

regexp_match(original_text, '\d{1,2}\/\d{1,2}\/\d{2}')

有了这个：

regexp_match(original_text, '\d{{1,2}}\/\d{{1,2}}\/\d{{2}}')

可能是 python format，你需要逃避你的 {}s。

KeyError:'1,2' running Postgresql regexp_match() in Jupyter Notebook

KeyError:'1,2' running Postgresql regexp_match() in Jupyter Notebook

sql

postgresql

python-3.x

jupyter-notebook