如何在 pygame 中与 2 张图片发生碰撞？

Question

所以我试图与 2 个图像发生碰撞，我什至使用了 get_rect 但仍然不适合我。在函数 draw 中，我试图与 player_rect 和 rect_img 发生碰撞，这是 GRASS_IMAGE 的图像，我们将不胜感激。

如果你想测试代码，创建 2 python 文件一个 main.py 和第二个 mapdata.py，主要包括我写的第一个代码，在地图数据中包括第二个。并更改 .png（图像）。

如果代码难以阅读或写得不好，我们深表歉意。

import pygame as pg
import sys
import os
from pygame import image
from pygame import rect
from mapdata import game_map_data

#CONSTANT VARIABLES
#WIDTH;HEIGHT
WINDOW_WIDTH = 800
WINDOW_HEIGHT = 598
PLAYER_WIDTH = 20
PLAYER_HEIGHT = 20
#COLORS
COLOR_DARKBLUE = 'darkblue'
COLOR_RED = 'red'
#WINDOW
WINDOW = pg.display.set_mode((WINDOW_WIDTH,WINDOW_HEIGHT))
sky = pg.image.load('sky.png')
sky = pg.transform.scale(sky,(800,599))

class Player(object):
    def __init__(self,x,y,width,height):
        self.x = x
        self.y = y
        self.width = width
        self.height = height

    def Draw(self):
        self.player = pg.image.load('player.png')
        self.player = pg.transform.scale(self.player,(PLAYER_WIDTH,PLAYER_HEIGHT))
        self.player_rect = self.player.get_rect()
        WINDOW.blit(self.player,dest=(self.x,self.y))
        self.player_rect.x = self.x
        self.player_rect.y = self.y

        if self.rect_img.colliderect(self.player_rect): #COLLISIONS DONT WORK
            print("collided")

    def handle_keys(self,speed):
        keys = pg.key.get_pressed()
        self.speed = speed
        if keys[pg.K_RIGHT]:
            self.x += speed
        if keys[pg.K_LEFT]:
            self.x -= speed
        if keys[pg.K_DOWN]:
            self.y+= speed
        if keys[pg.K_UP]:
            self.y -= speed

    ###########
    ##TILEMAP##
    ###########

    def tile(self,data,tile_size,img_size):
        self.tile_list = []

        #TEXTURES
        GRASS_IMAGE = pg.image.load('platform.jpg')
        #stone_img = pg.image.load('')

        row_count = 0
        self.tile_size = tile_size
        self.img_size = img_size

        for row in data:
            col_count = 0
            for tile in row:
                if tile == 1:
                    img = pg.transform.scale(GRASS_IMAGE,(img_size,img_size))
                    self.rect_img = img.get_rect()
                    self.rect_img.x = col_count * tile_size
                    self.rect_img.y = row_count * tile_size
                    tile = (img,self.rect_img)
                    self.tile_list.append(tile)
                col_count += 1
            row_count += 1


    def draw_tile(self):
        for tile in self.tile_list:
            WINDOW.blit(tile[0], tile[1])


#FPS
clock = pg.time.Clock()




game_map_data = game_map_data


#PLAYER
player = Player(x=30,y=30,width=PLAYER_WIDTH,height=PLAYER_HEIGHT)
gamemap = player.tile(game_map_data,17,20)
while True:
    FPS = 60
    pg.display.update()
    clock.tick(FPS)

    
    for event in pg.event.get():
        if event.type == pg.QUIT:
            sys.exit()

    SKY_POSITION = (0,0)

    WINDOW.blit(sky,SKY_POSITION)
    player.draw_tile()
    #player.col()
    player.Draw()
    player.handle_keys(speed=3)
    pg.display.update()
    pg.display.flip()

tilemap (mapdata.py)：实际地图

game_map_data = [
[1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,0,0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,0,0,0,0,0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1],
[1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1],
]

Answer 1

要使两个对象发生碰撞，您可以使用 colliderect： rect = 长方形

if Rect1.colliderect(Rect2):

然后通过使用它您可以确定当Rect1 与Rect2 发生碰撞时您希望Rect1 做什么。在这种情况下，我们希望玩家停止或被阻止。

 if Rect1.colliderect(Rect2):
   Rect1.bottom = Rect2.top #changing y pos
   Rect1.left = Rect2.right #changing x pos
   Rect1.right = Rect.left #changing x pos
   Rect1.top = Rect.bottom #changing y pos

这将使 Rect1 在碰到 Rect2 时停止移动。我不知道这是否有帮助，但我希望它能让您了解这次碰撞的可能性。

Answer 2

self.rect_img 是您通过 tile 函数中的 for 循环设置的最后一个草方块的矩形。所以，

self.rect_img.colliderect(self.player_rect):

实际上只是在测试最后一个草方块。

您需要针对所有图块进行测试，而不仅仅是最后一个图块。幸运的是，您将这些图块存储在一个列表中，因此您可以通过该列表检查玩家和所有图块。

 for t in self.tile_list:
      if t[1].colliderect(self.player_rect): #COLLISIONS DONT WORK
            print("collided")

此外，如果您加载和转换图像一次而不是每一帧，您的代码可能会更快。

如何在 pygame 中与 2 张图片发生碰撞？

How do I make a collision in pygame with 2 images?

python

pygame