如何从字符串中获取日期并对其进行格式化？

Question

我的服务器上有 PDF 文件保存如下：

945_20140610_Eve_Ikras.pdf

我想把年月日分开来

$file = "945_20140610_Eve_Ikras.pdf";

if(preg_match("/\d{4}\-d{2}\-d{2}/", $file, $match))
    print_r($match);

输出：

Array (
  [0] => 20140610
)

但我想像这样格式化日期：

2014-06-10

有什么建议吗？

Answer 1

最简单的方法就是创建一个 DateTime object (Since you have a special format here you have to use DateTime::createFromFormat to create your object) and then you can format your date as you want it with format()，例如

$file = "945_20140610_Eve_Ikras.pdf";

if(preg_match("/\d{4}\d{2}\d{2}/", $file, $match)) {
    $date = DateTime::createFromFormat("Ymd", $match[0]);
    echo $date->format("Y-m-d");
}

输出：

2014-06-10

如何从字符串中获取日期并对其进行格式化？

How can I grab a date out of a string and format it?

php

string

datetime

date

preg-match