如何调用指针函数
how to call pointer function
请告诉我如何调用下面的函数 twoSum
。它使用数据类型 int*
。我不知道如何去做。谢谢。
#include <stdio.h>
//int twoSum(nums, target);
int main() {
printf("Hello, World!\n");
int nums[10]= {2,7,11,15};
int target = 9;
int numsSize=3;
int retrunSize=3;
int a=twoSum(nums,numsSize,target,retrunSize);
return 0;
}
int* twoSum(int* nums, int numsSize, int target, int* returnSize) {
for (int i = 0; i < numsSize; ++i) {
for (int j = i + 1; j < numsSize; ++j) {
if (nums[i] + nums[j] == target) {
int* ret = malloc(sizeof(int) * 2);
ret[0] = i, ret[1] = j;
*returnSize = 2;
return ret;
}
}
}
*returnSize = 0;
return NULL;
}
根据评论中的有用建议,我得到了修改后的版本。但是printf(a)
什么都不给我:
#include <stdio.h>
//int twoSum(nums, target);
#include <stdlib.h>
int* twoSum(int* nums, int numsSize, int target, int* returnSize) {
for (int i = 0; i < numsSize; ++i) {
for (int j = i + 1; j < numsSize; ++j) {
if (nums[i] + nums[j] == target) {
int* ret = malloc(sizeof(int) * 2);
ret[0] = i, ret[1] = j;
*returnSize = 2;
return ret;
}
}
}
*returnSize = 0;
return NULL;
}
int main() {
printf("Hello, World!\n");
int nums[4]= {2,7,11,15};
int target = 13;
int numsSize=6;
int retrunSize=0;
int* a=twoSum(nums,numsSize,target,retrunSize);
printf(&a);
printf(*a);
return 0;
}
这是调试器显示的内容:
你可以参考下面,
#include <stdio.h>
#include <stdlib.h>
int* twoSum(int* nums, int numsSize, int target, int* returnSize) {
for (int i = 0; i < numsSize; ++i) {
for (int j = i + 1; j < numsSize; ++j) {
if (nums[i] + nums[j] == target) {
int* ret = malloc(sizeof(int) * 2);
ret[0] = i, ret[1] = j;
*returnSize = 2;
return ret;
}
}
}
*returnSize = 0;
return NULL;
}
//int twoSum(nums, target);
int main() {
printf("Hello, World!\n");
int i;
int* (*funptr)(int*, int, int, int*) = &twoSum; // function pointer declaration
int nums[10] = {2,7,11,15};
int target = 9;
int *returnSize = malloc(sizeof(int)); // need returnsize pointer vairable to collect return size
int *a=(*funptr)(nums, 10, target, returnSize); // function pointer calling
// Below are output statements
printf("returnSize = %d\n", *returnSize);
printf("Nums porsition are: ");
for (i = 0; i < *returnSize; i++) {
printf ("a[%d] = %d ", i, a[i]);
}
return 0;
}
请告诉我如何调用下面的函数 twoSum
。它使用数据类型 int*
。我不知道如何去做。谢谢。
#include <stdio.h>
//int twoSum(nums, target);
int main() {
printf("Hello, World!\n");
int nums[10]= {2,7,11,15};
int target = 9;
int numsSize=3;
int retrunSize=3;
int a=twoSum(nums,numsSize,target,retrunSize);
return 0;
}
int* twoSum(int* nums, int numsSize, int target, int* returnSize) {
for (int i = 0; i < numsSize; ++i) {
for (int j = i + 1; j < numsSize; ++j) {
if (nums[i] + nums[j] == target) {
int* ret = malloc(sizeof(int) * 2);
ret[0] = i, ret[1] = j;
*returnSize = 2;
return ret;
}
}
}
*returnSize = 0;
return NULL;
}
根据评论中的有用建议,我得到了修改后的版本。但是printf(a)
什么都不给我:
#include <stdio.h>
//int twoSum(nums, target);
#include <stdlib.h>
int* twoSum(int* nums, int numsSize, int target, int* returnSize) {
for (int i = 0; i < numsSize; ++i) {
for (int j = i + 1; j < numsSize; ++j) {
if (nums[i] + nums[j] == target) {
int* ret = malloc(sizeof(int) * 2);
ret[0] = i, ret[1] = j;
*returnSize = 2;
return ret;
}
}
}
*returnSize = 0;
return NULL;
}
int main() {
printf("Hello, World!\n");
int nums[4]= {2,7,11,15};
int target = 13;
int numsSize=6;
int retrunSize=0;
int* a=twoSum(nums,numsSize,target,retrunSize);
printf(&a);
printf(*a);
return 0;
}
这是调试器显示的内容:
你可以参考下面,
#include <stdio.h>
#include <stdlib.h>
int* twoSum(int* nums, int numsSize, int target, int* returnSize) {
for (int i = 0; i < numsSize; ++i) {
for (int j = i + 1; j < numsSize; ++j) {
if (nums[i] + nums[j] == target) {
int* ret = malloc(sizeof(int) * 2);
ret[0] = i, ret[1] = j;
*returnSize = 2;
return ret;
}
}
}
*returnSize = 0;
return NULL;
}
//int twoSum(nums, target);
int main() {
printf("Hello, World!\n");
int i;
int* (*funptr)(int*, int, int, int*) = &twoSum; // function pointer declaration
int nums[10] = {2,7,11,15};
int target = 9;
int *returnSize = malloc(sizeof(int)); // need returnsize pointer vairable to collect return size
int *a=(*funptr)(nums, 10, target, returnSize); // function pointer calling
// Below are output statements
printf("returnSize = %d\n", *returnSize);
printf("Nums porsition are: ");
for (i = 0; i < *returnSize; i++) {
printf ("a[%d] = %d ", i, a[i]);
}
return 0;
}