从数组中删除镜像对象

Question

我有一个问题，我真的不知道如何以好的方式解决

我有一个大致如下所示的对象数组：

[
    { name: "horse", newName: "owl" }
    { name: "owl", newName: "horse" }
    { name: "frog", newName: "dog" }
]

我想从这个数组中删除“镜像”对象，结果得到一个像这样的数组：

[
    { name: "frog", newName: "dog" }
]

基本上我需要找到具有相反键和值的对象

更复杂的场景：

[
    { name: "horse", newName: "frog" }
    { name: "owl", newName: "horse" }
    { name: "frog", newName: "owl" }
]

    // Result: []

[
    { name: "horse", newName: "frog" }
    { name: "dog", newName: "cat" }
    { name: "owl", newName: "horse" }
    { name: "frog", newName: "owl" }
    { name: "monkey", newName: "worm" }
    { name: "cat", newName: "dog" }
]

    // Result: [{ name: "monkey", newName: "worm" }]

在第一种情况下，我会简单地遍历数组，如果找到这样的对象：

{name: obj1.value2, newName: obj1.value1}我会拼接它们

但我不知道如何处理必须移除 3 个或更多对象的更复杂情况。有什么提示吗？

预先感谢您的时间

Answer 1

你可以通过在数组

上使用 filter 函数来完成

var data = [
    { name: "horse", newName: "frog" },
    { name: "dog", newName: "cat" },
    { name: "owl", newName: "horse" },
    { name: "frog", newName: "owl" },
    { name: "monkey", newName: "worm" },
    { name: "cat", newName: "dog" }
];


let noMirrored = data.filter(one => {
  return (
    !data.some(element => element.name === one.newName) &&
    !data.some(element => element.newName === one.name)
  );
});

console.log(noMirrored);

Answer 2

用一些来检查现值。

var array = [{
    name: "horse",
    newName: "frog"
  },
  {
    name: "dog",
    newName: "cat"
  },
  {
    name: "owl",
    newName: "horse"
  },
  {
    name: "frog",
    newName: "owl"
  },
  {
    name: "monkey",
    newName: "worm"
  },
  {
    name: "cat",
    newName: "dog"
  }
]

array.forEach(t => {

  var nameFound = array.some(a => a.name == t.newName);
  var newNameFound = array.some(a => a.newName == t.name);
  if (!nameFound && !newNameFound) {
    console.log(t);
  }
});

从数组中删除镜像对象

Remove mirrored objects from an array

javascript

arrays

object

javascript-objects