我可以跨数组公式中的多个列进行 COUNTIF 计算吗？

Question

我觉得很简单..

我想按照 =Countif(A2:X , "Yes")

我会用一个简单的 IF(A2:A = "" ,"" .....

将其包装在一个数组公式中

我希望它返回每行“是”的数量

所以如果第 2 行有 12 个是'然后带回 12，第 3 行有 7 个所以 7 等等

这在一定程度上奏效了，但返回了整个范围内的计数，而不是按行拆分

Answer 1

虽然有点乏味，但你做不到吗：

=COUNTIF(A2:A, "Yes") + COUNTIF(B2:B, "Yes") + COUNTIF(C2:C, "Yes") + COUNTIF(D2:D, "Yes") + COUNTIF(E2:E, "Yes") + COUNTIF(F2:F, "Yes") + COUNTIF(G2:G, "Yes") + COUNTIF(H2:H, "Yes") + COUNTIF(I2:I, "Yes") + COUNTIF(J2:J, "Yes") + COUNTIF(K2:K, "Yes") + COUNTIF(L2:L, "Yes") + COUNTIF(M2:M, "Yes") + COUNTIF(N2:N, "Yes") + COUNTIF(O2:O, "Yes") + COUNTIF(P2:P, "Yes") + COUNTIF(Q2:Q, "Yes") + COUNTIF(R2:R, "Yes") + COUNTIF(S2:S, "Yes") + COUNTIF(T2:T, "Yes") + COUNTIF(U2:U, "Yes") + COUNTIF(V2:V, "Yes") + COUNTIF(W2:W, "Yes") + COUNTIF(X2:X, "Yes")

Answer 2

尝试：

=ArrayFormula(IF(A2:A="",,MMult(N(A2:X="Yes"),Sequence(Columns(A2:X))^0)))

或

=ArrayFormula(IF(A2:A="",,Len(RegexReplace(RegexReplace(Transpose(Query(Transpose(A2:X),,9^9)),"(?i)\bYes\b","~"),"[^~]",))))

或

=ArrayFormula(IF(A2:A="",,Len(Substitute(Transpose(Query(Transpose(IF(A2:X<>"Yes",,"~")),,9^9))," ",))))

更新

If I wanted to ammend this formula to do if A2:X = No AND A1:X1 contains, for instance (AG) how would I do this?

=ArrayFormula(IF(A2:A="",,MMult((A2:X="No")*RegexMatch(A1:X1,"AG"),Sequence(Columns(A2:X))^0)))

我可以跨数组公式中的多个列进行 COUNTIF 计算吗？

Can I COUNTIF across multiple columns in an array formula?

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