使用循环在 python 中通过数组制作直角三角形并自动填充数组

Question

我想编写一个程序来帮助我使用 python 计算一些值。主要想法是我想制作一个 table，其中只有一半的单元格具有价值。（也就是说我要做一个三角形）所以，我要做的三角形就是这样的格式。

但是，事情并没有那么容易。请参阅下面的 table。（也与 picture 1 相同）

6.00 6.45 6.80 7.10 7.36 7.56 7.77
6.90 7.20 7.47 7.70 7.88 8.06
7.50 7.75 7.97 8.12 8.30
8.00 8.20 8.33 8.50
8.40 8.50 8.67
8.60 8.80
9.00

在上面的三角形中，每一行都是根据特定公式从上一行生成的。请参考picture 2 and picture 3.

另外，请注意，在上面的三角形中，每个单元格都乘以 100。例如，左上角的 6.00 确实是 6%（0.06）。 <<请不要在我的程序中将数字乘以100，因为这只是为了演示而发生的意外。

好的。所以，我想做一个程序，只要我输入第一行，程序就会为我计算并显示剩余的行。（这意味着显示整个三角形）

下面是我的代码。请看一看。我试过写一个框架，但是遇到了两个问题

我不知道如何根据我在程序中输入的第一个数组（第一行）自动填充我的其他数组（其他行）。
当我尝试运行我的程序时，我不断收到“IndexError：列表索引超出范围”的错误。

这是我的代码

array1 = [0.06,0.0645,0.068,0.071,0.0736,0.0756,0.0777]         #This is the initial array that I input
array2 = []            #This should be the output after the first iteration, I hope that my programme can auto fill the remaining arrays (including this array) after I run my programme
array3 = []            #This is a blank array waiting for auto fill after I run my program
array4 = []            #This is a blank array waiting for auto fill after I run my program
array5 = []            #This is a blank array waiting for auto fill after I run my program
array6 = []            #This is a blank array waiting for auto fill after I run my program
array7 = []            #This is a blank array waiting for auto fill after I run my program
array8 = []            #This is a blank array waiting for auto fill after I run my program


r = 0  # Set the initial position for the table that I want to make, and this is similar to the x-asis. Please refer to picture 2.
s = 1  # Set the initial position for the table that I want to make, and this is similar to the y-asis. Please refer to picture 2.



def SpotRateForcast(i,j,k):
    global r
    global s
    
    while (r <= len(k)):                                     # I try to make the first loop here
        s = 1                                                # Reset the value when the first row is completed such that the second loop can work in the second row
        while (s <= len(k)):                                 # this is the second loop to determine when to stop in the each row
            x = ((((1 + k[j - 1])**j) / ((1 + k[i - 1])**i))**(1/(j-i))) - 1  #Calculate the value by the certain formula
            print(("%.4f" % round(x,4)), end=' ,  ')         #Print the value up to 4 decimal places  
            s += 1                                           #Record one value is calculated and done
            SpotRateForcast(i,j+1,k)                         #Start to calculate and print the next value                         
        r += 1                                               # Switch to the next row when the second loop is finished
        
        
SpotRateForcast(r,s,array1)                                  #The code to run the program

感谢您阅读我的问题。我想请人帮我完成程序。如您所见，我的编码可能很糟糕，因为我是编程新手。但是我已经尽力做到了我能做的一切

我不介意你修改我的代码。如果你能帮我写一个新的代码就更好了。而且我可以向你学习如何编写更好的代码。

最后，我还有一个要求。请在您编写的代码中添加许多注释，否则我可能无法理解您写的内容（我是初学者）。非常感谢！

Answer 1

array=[[0.06,0.0645,0.068,0.071,0.0736,0.0756,0.0777]]

n = len(array[0])

#outer loop

for i in range(1, n):

       #append new row

    array.append([])
    
    for j in range(n-i):
        #i dont understand your calculations but they'd stand
        array[i][j] = #here

Answer 2

你想多了

如果您只需要打印一个三角形，只需按顺序打印每一行，然后按顺序打印每一行的值：

S = [0.06,0.0645,0.068,0.071,0.0736,0.0756,0.0777]

n = len(S)

print(('{:0.4f} ' * n).format(*S))  # print initial line

for i in range(1,n):                # loop over rows
    for j in range(i+1, n+1):       # then over colums
        num = (1 + S[j -1])**j
        den = (1 + S[i - 1])**i
        x = (num/den)**(1/(j - i)) -1       # ok we have f(i, j)
        print('{:0.4f}'.format(x), end=' ') # print it followed with a space 
    print('')                       # add a newline after a full row

它给出：

0.0600 0.0645 0.0680 0.0710 0.0736 0.0756 0.0777 
0.0690 0.0720 0.0747 0.0770 0.0787 0.0807 
0.0750 0.0775 0.0797 0.0812 0.0830 
0.0801 0.0821 0.0833 0.0850 
0.0841 0.0849 0.0867 
0.0857 0.0880 
0.0904

现在，如果您想首先构建数组，因为您稍后会 post-process 它们，只需将每个字段值附加到该行的列表，然后将这些列表中的每一个附加到列表的全局列表

S = [0.06,0.0645,0.068,0.071,0.0736,0.0756,0.0777]

n = len(S)

result = [S]                        # add the initial row

for i in range(1,n):                # loop over rows
    row = []                            # prepare a new list for the row
    result.append(row)                  # and append it to result
    for j in range(i+1, n+1):       # then over colums
        num = (1 + S[j -1])**j
        den = (1 + S[i - 1])**i
        x = (num/den)**(1/(j - i)) -1       # ok we have f(i, j)
        row.append(x)               # as a list is modifiable we can append to it

使用循环在 python 中通过数组制作直角三角形并自动填充数组

Making a right triangle by arrays in python using loops and auto filling the arrays

python

arrays

math

loops