PHP 将函数从循环更改为递归
PHP change a function from from loops to recursion
我有以下 JSON 对象:
{
"id": 1,
"name": null,
"block": {
"type": "none",
"descends": [
{
"operation":"sum",
"descends":[
{
"label":2,
"value":false
}
]
},
{
"label": 1,
"value": 3,
},
{
"label": 2,
"value": 2
}
],
"label": 1,
"value": true
}
}
我想收集所有 label
和 value
属性并将它们存储在一个数组中,所以我创建了以下函数:
public function collectValues($arr){
$finalValues = [];
foreach($arr as $key => $element){
if($key=='block'){
foreach($element as $key2 => $block){
if($key2=='descends'){
foreach($block as $key3 => $node_block){
if($key3=='descends'){
foreach($node_block as $key4 => $anotherNode){
if($key4 == 'descends'){
foreach($anotherNode as $finalNode){
$finalValues [] = array('lable'=>$finalNode->label, 'value' =>$finalNode->value);
}
}
}
}
else{
$finalValues [] = array('lable' => $node_block->label, 'value' => $node_block->value);
}
}
}
}
$finalValues [] = array('lable'=> $element->label, 'value' => $element->value);
}
}
return $finalValues;
}
函数有效,我得到以下信息:
[
{
"lable": 2,
"value": false
},
{
"lable": 1,
"value": 3
},
{
"lable": 2,
"value": 2
},
{
"lable": 1,
"value": true
}
]
问题是 JSON 对象可以包含更多 descends
,例如:
{
"id": 1,
"name": null,
"block": {
"type": "none",
"descends": [
{
"operation":"sum",
"descends":[
{
"operation":"sum",
"descends":[
{
"label":2,
"value":false
}
],
"label":2,
"value":false
}
]
},
{
"operation":"sum",
"descends":[
{
"label":2,
"value":false
}
],
"label": 1,
"value": 3,
},
{
"label": 2,
"value": 2
}
],
"label": 1,
"value": true
}
}
这意味着我将不得不添加更多的 foreach 循环。处理这种情况的一个好方法是使用递归。如何将上述函数转换为递归函数?
你的循环函数没有意义去改变。更容易从头开始重写
这是我的递归用例。也许有更简单的选择,但我没有追求优化
$array = json_decode($json, true); //in $json your JSON)
$result = []; // array for result
checkLabel($array, $result);
print_r($result);
function checkLabel(array $array, &$result){
//first check every element on nested array
foreach ($array as $key => $value){
if (is_array($value)) {
//if found call recursive function
checkLabel($value, $result);
}
}
//then check 'label' key.. its mean we have attribute
if (array_key_exists('label', $array)) {
//save it
$result[] = [
'label' => $array['label'],
'value' => $array['value']??'' //if have label but without value)
];
}
}
我有以下 JSON 对象:
{
"id": 1,
"name": null,
"block": {
"type": "none",
"descends": [
{
"operation":"sum",
"descends":[
{
"label":2,
"value":false
}
]
},
{
"label": 1,
"value": 3,
},
{
"label": 2,
"value": 2
}
],
"label": 1,
"value": true
}
}
我想收集所有 label
和 value
属性并将它们存储在一个数组中,所以我创建了以下函数:
public function collectValues($arr){
$finalValues = [];
foreach($arr as $key => $element){
if($key=='block'){
foreach($element as $key2 => $block){
if($key2=='descends'){
foreach($block as $key3 => $node_block){
if($key3=='descends'){
foreach($node_block as $key4 => $anotherNode){
if($key4 == 'descends'){
foreach($anotherNode as $finalNode){
$finalValues [] = array('lable'=>$finalNode->label, 'value' =>$finalNode->value);
}
}
}
}
else{
$finalValues [] = array('lable' => $node_block->label, 'value' => $node_block->value);
}
}
}
}
$finalValues [] = array('lable'=> $element->label, 'value' => $element->value);
}
}
return $finalValues;
}
函数有效,我得到以下信息:
[
{
"lable": 2,
"value": false
},
{
"lable": 1,
"value": 3
},
{
"lable": 2,
"value": 2
},
{
"lable": 1,
"value": true
}
]
问题是 JSON 对象可以包含更多 descends
,例如:
{
"id": 1,
"name": null,
"block": {
"type": "none",
"descends": [
{
"operation":"sum",
"descends":[
{
"operation":"sum",
"descends":[
{
"label":2,
"value":false
}
],
"label":2,
"value":false
}
]
},
{
"operation":"sum",
"descends":[
{
"label":2,
"value":false
}
],
"label": 1,
"value": 3,
},
{
"label": 2,
"value": 2
}
],
"label": 1,
"value": true
}
}
这意味着我将不得不添加更多的 foreach 循环。处理这种情况的一个好方法是使用递归。如何将上述函数转换为递归函数?
你的循环函数没有意义去改变。更容易从头开始重写 这是我的递归用例。也许有更简单的选择,但我没有追求优化
$array = json_decode($json, true); //in $json your JSON)
$result = []; // array for result
checkLabel($array, $result);
print_r($result);
function checkLabel(array $array, &$result){
//first check every element on nested array
foreach ($array as $key => $value){
if (is_array($value)) {
//if found call recursive function
checkLabel($value, $result);
}
}
//then check 'label' key.. its mean we have attribute
if (array_key_exists('label', $array)) {
//save it
$result[] = [
'label' => $array['label'],
'value' => $array['value']??'' //if have label but without value)
];
}
}