如何使用 jq（或 python）删除某些 JSON 中的特定键（？）？

Question

这里是输入json。它是从 Red Hat Satellite 中提取的 puppet class 的部分 JSON 转储。

{
  "Id": 9999,
  "Match": "fqdn=server.fqdn.com",
  "Value": {
    "user1": {
      "order": 90,
      "nofile": {
        "comment": "I want to lose this comment",
        "soft": "65535",
        "hard": "65535"
      },
      "nproc": {
        "comment": "I want to lose this also",
        "soft": "32768",
        "hard": "32768"
      }
      },
    "user2": {
      "order": 90,
      "nofile": {
        "comment": "I want to lose this comment",
        "soft": "65535",
        "hard": "65535"
      },
      "nproc": {
        "comment": "I want to lose this also",
        "soft": "32768",
        "hard": "32768"
      }
    }
  }
}

我想删除所有的“评论”。我找不到执行此操作的示例，也找不到对一般执行此操作的解释。或者我太笨了，无法理解我目前所读的内容。

所以我的输出是

{
  "Id": 9999,
  "Match": "fqdn=server.fqdn.com",
  "Value": {
    "user1": {
      "order": 90,
      "nofile": {
        "soft": "65535",
        "hard": "65535"
      },
      "nproc": {
        "soft": "32768",
        "hard": "32768"
      }
      },
    "user2": {
      "order": 90,
      "nofile": {
        "soft": "65535",
        "hard": "65535"
      },
      "nproc": {
        "soft": "32768",
        "hard": "32768"
      }
    }
  }
}

有人要吗？

Answer 1

del( .. | objects | .comment )

Demo 在 jqplay

在 Python 中，它看起来像这样：

def remove_comments(node):
   if isinstance(node, dict):
      if 'comment' in node:
         del node['comment']
      for child in node.values():
         remove_comments(child)
   elif isinstance(node, list):
      for child in node:
         remove_comments(child)

如何使用 jq（或 python）删除某些 JSON 中的特定键（？）？

How to use jq (or python) to remove a particular key(?) in some JSON?

python

json

nested-lists

jq