获取 bootstrap 下拉值 return 在烧瓶中工作

Question

我正在尝试从下拉菜单中获取一个值（玩家）select。单击下拉按钮后，我希望将值 'player' 发送到 flask 并在网站上呈现新玩家的图像。 HTML:

<form method="POST">
    <div class="input-group">
      <select class="custom-select" id="inputGroupSelect04" name="player" value="{{ player }}">
          {% for key, value in team.items() %}
            <option value={{ value }}>{{ value }}</option>
          {% endfor %}
      </select>
      <div class="input-group-append">
        <button class="btn btn-outline-secondary" type="submit">Select</button>
      </div>
    </div>

</form>
    <img src="/static/{{ player }}.png" alt="{{ player }}">

烧瓶：

@app.route("/", methods=['POST', 'GET'])
def main_page():
    player = okc[1628983]
    if request.method == "POST":
        print("this posted")
        player = request.form.get('player')
        print(request.form.get('player'))
        return render_template("index.html", team=okc, player=player)
    return render_template("index.html", team=okc, player=player)

Answer 1

而不是你的：

player = request.form.get('player')

你可以试试这个：

player = request.form['player']

Answer 2

按钮未发布 - 将类型从按钮更改为提交

获取 bootstrap 下拉值 return 在烧瓶中工作

Getting bootstrap dropdown value return to work in flask

html

flask

python-3.x

bootstrap-4