Select 加入多对多和计算一对多

Question

我有两个查询，在一个地方我同时需要它们。我该如何修改第一个？

第一个（一对多）：

    const server = await Server.findOne({
      where: { id },
      attributes: {
        include: [[Sequelize.fn('COUNT', Sequelize.col('users.id')), 'localUserCount']],
      },
      include: [{ model: User, attributes: [] }],
      group: ['Server.id'],
      raw: true,
    });

第二个（多对多）：

    const serverWithAdmins = await Server.findOne({
      where: { id },
      include: [{ model: AdminUser, as: 'adminUserList', through: { attributes: [] } }],
    });

我需要这样的东西：

    const server = await Server.findOne({
      where: { id },
      attributes: {
        include: [[Sequelize.fn('COUNT', Sequelize.col('users.id')), 'userCount']],
      },
      include: [
        { model: User, attributes: [] },
        // New line
        { model: AdminUser, as: 'adminUserList', through: { attributes: [] } }
      ],
      group: ['Server.id'],
      raw: true,
    });

但是在最后一个查询中我得到了这样的错误：

"column \"adminUserList.id\" must appear in the GROUP BY clause or be used in an aggregate function"

我想将 AdminUser 属性添加到 group 或添加 attributes，但我仍然无法为 Server 获取 AdminUser 的数组就像在第二个查询中一样。是否可以使用聚合函数 COUNT 并在一个查询中加入另一个关系？

Answer 1

您需要使用子查询将 Sequelize.fn 转换为 Sequelize.literal，并从 include 选项和 group 选项中删除 User：

const server = await Server.findOne({
      where: { id },
      attributes: {
        include: [
         [Sequelize.literal('(SELECT COUNT(*) FROM Users where Users.serverId=Server.id)'), 'userCount']
         ],
      },
      include: [
        { model: AdminUser, as: 'adminUserList', through: { attributes: [] } }
      ],
    });

Select 加入多对多和计算一对多

Select with joining many-to-many and count one-to-many

postgresql

node.js

sequelize.js