使用 python 导出 gpx 文件？

Question

我想从 https://routing.openstreetmap.de 导出（下载）gpx 文件当你问路时 url 是这样的： https://routing.openstreetmap.de/?z=17&center=51.515199%2C-0.092772&loc=51.514739%2C-0.089800&loc=51.516214%2C-0.096656&hl=en&alt=0&srv=1

使用 python 我想在将新的 loc=lat-lon&loc=lat-lon 插入 url 后导出 gpx 文件。在检查站点后，要下载的跨度 class。

请大家。至少一个提示

EDITED 这部分是在回答后添加的

这是 gpx 文件 https://routing.openstreetmap.de/?z=15&center=36.614839%2C3.014159&loc=36.600473%2C2.994676&loc=36.623863%2C3.002186&hl=en&alt=0&srv=2

并且在 json 请求下，我使用此代码仅获得两分：

import requests
import json

lat_start = 36.5924
lon_start = 2.9898

lat_dist = 36.6429
lon_dist = 2.9929

url = 'https://routing.openstreetmap.de/routed-car/route/v1/driving/'+ str(lat_start)+','+str(lon_start)+';'+str(lat_dist)+','+str(lon_dist)+'?overview=false&alternatives=true&steps=true'
#url = 'https://routing.openstreetmap.de/routed-car/route/v1/driving/-0.0898,51.514739;-0.096656,51.516214?overview=false&alternatives=true&steps=true'
response = requests.get(url)

data = response.json()
print('DATA ___________________________________________________')
print(data)
mrks = []
for elements in data['routes']:
    #print('ROUTES___________________________________________________')
    #print(elements)
    for legs in elements['legs']:
        #print('legs___________________________________________________')
        #print(legs)
        for steps in legs['steps']:
            #print('steps___________________________________________________')
            #print(steps)
            for intersections in steps['intersections']:
                #print('intersections___________________________________________________')
                #print(intersections)
                for location in intersections['location']:  
                    #print(location)
                    mrks.append(location)

#print(mrks)
twin = []
for i in range(0, len(mrks),2):
    twin.append(str(mrks[i])+'___'+str(mrks[i+1]))
print('points ___________________________________________________')   
for points in twin:
    print(points)

Answer 1

它似乎使用 JavaScript 从 API 获取数据作为 JSON 并在内存中创建数据（blob 和 gpx 数据），当您单击它时，它会直接从内存中发送数据 (blob) - 因此没有 URL 可以获取它。当我使用 click() 时，它会询问文件夹，这需要手动单击。

看起来 JSON 比 gpx
更简单 url 到 JSON 数据也使用 -0.0898,51.514739;-0.096656,51.516214

编辑： Link 到网页使用 lat,lon 但 link 到 JSON 需要 lon,lat

import requests

start_lon = -0.0898    # can be also as text
start_lat = 51.514739  # can be also as text

end_lon = -0.096656    # can be also as text
end_lat = 51.516214    # can be also as text

data = f"{start_lon},{start_lat};{end_lon},{end_lat}"

transport = 'bike'  # 'car', 'foot'

url = f'https://routing.openstreetmap.de/routed-{transport}/route/v1/driving/{data}'

payload = {
    'overview': 'false',     # can't be True/False
    'alternatives': 'true',  # can't be True/False
    'steps': 'true',         # can't be True/False
}

response = requests.get(url, params=payload)
print(response.url)
#print(response.text)
print('---')

data = response.json()

for point in data['waypoints']:
    print('name:', point['name'])
    print('distance:', point['distance'])
    print('location:', point['location'])
    print('---')

结果：

url: https://routing.openstreetmap.de/routed-bike/route/v1/driving/-0.0898,51.514739;-0.096656,51.516214?overview=false&alternatives=true&steps=true
---
name: Princes Street
distance: 4.955845
location: [-0.089734, 51.514722]
---
name: Gresham Street
distance: 8.8597
location: [-0.096605, 51.516287]
---

编辑：

Routing and python modules PyrouteLib, SimpleOsmRouter

的一些文档

使用 python 导出 gpx 文件？

export gpx file with python?

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