R中的动态过滤器
dynamic filter in R
我有一个数据集销售和另一个数据集促销。
促销数据集包含促销发生时间的详细信息。现在，我需要确定与特定促销相关的销售数据。
我提取了第一行并创建了一个过滤器
promo.filter="product.no==1100001369 & (customer.state==TN | customer.state==AP) & (cgrp==12 | cgrp==13)"
尝试过
promo.sales<-filter(sales, promo.filter)
我收到以下错误
Error: filter condition does not evaluate to a logical vector.
如何完成此操作。
尝试filter_(sales, promo.filter)
来自 non-standard evaluation 小插图：
Every function in dplyr that uses NSE also has a version that uses SE.
There’s a consistent naming scheme: the SE is the NSE name with _ on
the end. For example, the SE version of summarise() is summarise_(),
the SE version of arrange() is arrange_(). These functions work very
similarly to their NSE cousins, but the inputs must be “quoted”
我有一个数据集销售和另一个数据集促销。 促销数据集包含促销发生时间的详细信息。现在，我需要确定与特定促销相关的销售数据。
我提取了第一行并创建了一个过滤器
promo.filter="product.no==1100001369 & (customer.state==TN | customer.state==AP) & (cgrp==12 | cgrp==13)"
尝试过
promo.sales<-filter(sales, promo.filter)
我收到以下错误
Error: filter condition does not evaluate to a logical vector.
如何完成此操作。
尝试filter_(sales, promo.filter)
来自 non-standard evaluation 小插图：
Every function in dplyr that uses NSE also has a version that uses SE. There’s a consistent naming scheme: the SE is the NSE name with
_on the end. For example, the SE version ofsummarise()issummarise_(), the SE version ofarrange()isarrange_(). These functions work very similarly to their NSE cousins, but the inputs must be “quoted”