如何为我自己的代码编辑器的不同文件夹的 python 文件创建函数？

Question

我正在创建代码编辑器，但我的代码只是运行 python 文件，该文件位于代码编辑器文件所在的同一文件夹中当我在侧栏中打开另一个文件夹并从 select 中打开一个文件运行时，我的终端显示错误我尝试了很多次，但我无法修复它请告诉我如何修复它

错误：-

python: can't open file 'D:\coding notes\pytho project\Anmol.py': [Errno 2] No such file or directory

这是我的代码:-

import os
import subprocess
from tkinter import*
from tkinter import ttk
from tkinter.filedialog import askdirectory, asksaveasfilename
def process_directory(parent,path):
    for i in os.listdir(path):
        abspath = os.path.join(path,i)
        dirv = os.path.isdir(abspath)
        oid = tree.insert(parent,END,text=i,open=False)
        if dirv:
            process_directory(oid,abspath)
def Open(event=None):
    global path
    for i in tree.get_children():
        tree.delete(i)
    path = askdirectory()
    abspath = os.path.abspath(path)
    root_node = tree.insert("",END,text=abspath,open=True)
    process_directory(root_node,abspath)
def select_file(event=None):
    global file
    item = tree.selection()
    file = tree.item(item,"text")
    abspath = os.path.join(path,file)
    editor.delete(1.0,END)
    with open(abspath,"r") as f:
        editor.insert(1.0,f.read())
def save(event=None):
    global file
    if file == "":
        saveas()
    else:
        item = tree.selection()
        file = tree.item(item,"text")
        filepath = os.path.join(path,file)
        with open(file,"w") as f:
            f.write(editor.get(1.0,END))
        root.title(os.path.basename(file) + "-Python")
def saveas(event=None):
    global file
    file = asksaveasfilename(defaultextension=".py",filetypes=[("Python Files","*.py")])
    if file == "":
        file = None
    else:
        with open(file,"w") as f:
            f.write(editor.get(1.0,END))
        root.title(os.path.basename(file) + "-Python")
def run(event=None):
    global file
    if file == "":
        pass
    else:
        command = f"python {file}"
        run_file = subprocess.Popen(command,stdout=subprocess.PIPE,stderr=subprocess.PIPE,shell=True)
        Output, error = run_file.communicate()
        output.insert(END,f"{file}>>\n")
        output.insert(END,Output)
        output.insert(END,error)
root = Tk()
tree = ttk.Treeview()
tree.pack(side=LEFT,fill=BOTH)
file = ""
path = ""
editor = Text()
editor.pack(expand=True,fill=BOTH)
output = Text(height=15)
output.pack(expand=True,fill=BOTH)

root.bind("<Control-Alt-o>",Open)
root.bind("<Control-s>",save)
root.bind("<Control-Alt-s>",saveas)
root.bind("<Shift-Return>",run)
tree.bind("<<TreeviewSelect>>",select_file)





root.mainloop()

Answer 1

如果所选文件位于所选文件夹的 sub-folder 内，则 select_file() 内由 abspath = os.path.join(path,file) 创建的 绝对路径 是不是正确的绝对路径（错过了 sub-folder 信息）。

其中一种方法是在插入树视图时在values选项中保存绝对路径：

def process_directory(parent,path):
    for i in os.listdir(path):
        abspath = os.path.join(path,i)
        dirv = os.path.isdir(abspath)
        # save the absolute path in "values" option
        oid = tree.insert(parent,END,text=i,open=False,values=(abspath,))
        if dirv:
            process_directory(oid,abspath)

然后在select_file()里面可以通过获取values选项获取绝对路径，而不是加入选中的文件夹和选中的文件：

def select_file(event=None):
    global file
    item = tree.selection()
    # get the absolute path
    file = tree.item(item,"values")[0]
    if os.path.isfile(file):
        editor.delete(1.0,END)
        with open(file,"r") as f:
            editor.insert(1.0,f.read())

同样适用于 save()。

如何为我自己的代码编辑器的不同文件夹的 python 文件创建函数？

How to create function to python file of different folder my own code editor?

python

tkinter