如何根据对象中的另一个数组过滤数组？

Question

我有一个数组：

const arr = [
    {id: 1, text: "hello", likes: [1,2,5]},
    {id: 2, text: "text", likes: []},
    {id: 3, text: "example", likes: [1]}
]

如何根据 likes 数组的长度过滤它，即数组应该是这样的：

const arr = [
        {id: 1, text: "hello", likes: [1,2,5]},
        {id: 3, text: "example", likes: [1]},
        {id: 2, text: "text", likes: []},
    ]

Answer 1

您可以使用带有参数 a,b 的 Array.prototype.sort() 并比较 likes 属性

的长度属性

在此处阅读更多内容： javascript Array.prototype.sort

const arr = [
    {id: 1, text: "hello", likes: [1,2,5]},
    {id: 2, text: "text", likes: []},
    {id: 3, text: "example", likes: [1]}
]

arr.sort(function(a,b) { 
   return b.likes.length - a.likes.length;
});

for(let a = 0; a < arr.length; a++){
  console.log(arr[a]);
}

如何根据对象中的另一个数组过滤数组？

How to filter an array according another array in object?

javascript

arrays

filtering