AJAX JSON HTML JS如何输出数据table?
AJAX JSON HTML JS How to output data table?
HTML:
<table>
<tr>
<th>Student Name</th>
<th>Student Grades</th>
</tr>
<tr>
<td>
<select name="dropdown" id="dropdown">
<option> - </option>
<option id = "StudentA"> Student A </option>
<option id = "StudentB"> Student B </option>
</select>
</td>
<td></td>
<td></td>
</tr>
<tr>
<td>
<select name="dropdown" id="dropdown">
<option> - </option>
<option id = "StudentA"> Student A </option>
<option id = "StudentB"> Student B </option>
</select>
</td>
<td></td>
<td></td>
</tr>
</table>
JSON:
{"students":
[ {"studentName" : "studentA", "studentGrades" : "gradeC"}, {"studentName" : "studentB", "studentGrades" : "gradeA+"},
]
}
当我 select 学生 A 的下拉选项时,如何让学生成绩自动显示在 table 上?
我只解析了 responsetext 并做了一个控制台日志并完成了它我让所有的学生都在控制台日志上但不确定如何使用 select 选项下拉列表来完成它。
您可以尝试以下方法来实现。在 select 标签上添加 onchange
事件,并根据 selected 选项更新成绩列。
完整的工作代码:
const data = {
"students": [{
"studentName": "studentA",
"studentGrades": "gradeC"
}, {
"studentName": "studentB",
"studentGrades": "gradeA+"
}, ]
}
function showGrades() {
const dropdowns = document.querySelectorAll('#dropdown')
dropdowns.forEach(dropdown => {
const selectedVal = dropdown.options[dropdown.selectedIndex].id
const formattedVal = selectedVal.charAt(0).toLowerCase() + selectedVal.slice(1)
const grades = data.students.map(item => {
if (item.studentName == formattedVal) {
dropdown.parentElement.parentElement.children[1].innerText = item.studentGrades;
}
})
})
}
<table>
<tr>
<th>Student Name</th>
<th>Student Grades</th>
</tr>
<tr>
<td>
<select name="dropdown" id="dropdown" onchange="showGrades()">
<option> - </option>
<option id="StudentA"> Student A </option>
<option id="StudentB"> Student B </option>
</select>
</td>
<td></td>
</tr>
<tr>
<td>
<select name="dropdown" id="dropdown" onchange="showGrades()">
<option> - </option>
<option id="StudentA"> Student A </option>
<option id="StudentB"> Student B </option>
</select>
</td>
<td></td>
</tr>
</table>
希望这就是您希望它的工作方式。
您可以通过在 select 上触发 onchange
事件来实现它,然后使用 Array.filter()
方法过滤掉学生数组以获得 selected 选项 studentGrade
.
工作演示:
const obj = {
"students": [
{"studentName" : "studentA", "studentGrades" : "gradeC"},
{"studentName" : "studentB", "studentGrades" : "gradeA+"},
]
};
function getGrades() {
const selectedOption = document.getElementById('dropdown').value;
document.getElementById('studentGrade').innerHTML = obj.students.find((obj) => obj.studentName === selectedOption).studentGrades;
}
<table>
<tr>
<th>Student Name</th>
<th>Student Grades</th>
</tr>
<tr>
<td>
<select name="dropdown" id="dropdown" onchange="getGrades()">
<option> - </option>
<option value="studentA"> Student A </option>
<option value="studentB"> Student B </option>
</select>
</td>
<td id="studentGrade"></td>
</tr>
</table>
HTML:
<table>
<tr>
<th>Student Name</th>
<th>Student Grades</th>
</tr>
<tr>
<td>
<select name="dropdown" id="dropdown">
<option> - </option>
<option id = "StudentA"> Student A </option>
<option id = "StudentB"> Student B </option>
</select>
</td>
<td></td>
<td></td>
</tr>
<tr>
<td>
<select name="dropdown" id="dropdown">
<option> - </option>
<option id = "StudentA"> Student A </option>
<option id = "StudentB"> Student B </option>
</select>
</td>
<td></td>
<td></td>
</tr>
</table>
JSON:
{"students":
[ {"studentName" : "studentA", "studentGrades" : "gradeC"}, {"studentName" : "studentB", "studentGrades" : "gradeA+"},
]
}
当我 select 学生 A 的下拉选项时,如何让学生成绩自动显示在 table 上?
我只解析了 responsetext 并做了一个控制台日志并完成了它我让所有的学生都在控制台日志上但不确定如何使用 select 选项下拉列表来完成它。
您可以尝试以下方法来实现。在 select 标签上添加 onchange
事件,并根据 selected 选项更新成绩列。
完整的工作代码:
const data = {
"students": [{
"studentName": "studentA",
"studentGrades": "gradeC"
}, {
"studentName": "studentB",
"studentGrades": "gradeA+"
}, ]
}
function showGrades() {
const dropdowns = document.querySelectorAll('#dropdown')
dropdowns.forEach(dropdown => {
const selectedVal = dropdown.options[dropdown.selectedIndex].id
const formattedVal = selectedVal.charAt(0).toLowerCase() + selectedVal.slice(1)
const grades = data.students.map(item => {
if (item.studentName == formattedVal) {
dropdown.parentElement.parentElement.children[1].innerText = item.studentGrades;
}
})
})
}
<table>
<tr>
<th>Student Name</th>
<th>Student Grades</th>
</tr>
<tr>
<td>
<select name="dropdown" id="dropdown" onchange="showGrades()">
<option> - </option>
<option id="StudentA"> Student A </option>
<option id="StudentB"> Student B </option>
</select>
</td>
<td></td>
</tr>
<tr>
<td>
<select name="dropdown" id="dropdown" onchange="showGrades()">
<option> - </option>
<option id="StudentA"> Student A </option>
<option id="StudentB"> Student B </option>
</select>
</td>
<td></td>
</tr>
</table>
希望这就是您希望它的工作方式。
您可以通过在 select 上触发 onchange
事件来实现它,然后使用 Array.filter()
方法过滤掉学生数组以获得 selected 选项 studentGrade
.
工作演示:
const obj = {
"students": [
{"studentName" : "studentA", "studentGrades" : "gradeC"},
{"studentName" : "studentB", "studentGrades" : "gradeA+"},
]
};
function getGrades() {
const selectedOption = document.getElementById('dropdown').value;
document.getElementById('studentGrade').innerHTML = obj.students.find((obj) => obj.studentName === selectedOption).studentGrades;
}
<table>
<tr>
<th>Student Name</th>
<th>Student Grades</th>
</tr>
<tr>
<td>
<select name="dropdown" id="dropdown" onchange="getGrades()">
<option> - </option>
<option value="studentA"> Student A </option>
<option value="studentB"> Student B </option>
</select>
</td>
<td id="studentGrade"></td>
</tr>
</table>