如何 select 最大前 10 (n) 行的大小？

Question

我已经有了下面的查询，它获取了 tables 的大小。但是，我只对获得最大尺寸 table 的前 10 名感兴趣。

怎么做？

select convert(varchar(30),o.name) AS table_name,
row_count(db_id(), o.id) AS row_count,
data_pages(db_id(), o.id, 0) AS pages,
data_pages(db_id(), o.id, 0) * (@@maxpagesize/1024) AS kbs
from sysobjects o
where type = 'U'
order by table_name

正在搜索类似的：select top 10 max(datapages) from sysobjects

编辑：

现在我还必须获取索引的大小，将 sysindexes 添加到查询中就足够了，或者应该添加另一个系统 table，例如 syscomments ?

这样写就是给了我 top table name:

select top 10 convert(varchar(30),o.name) AS table_name,
row_count(db_id(), o.id) AS row_count,
data_pages(db_id(), o.id, 0) AS pages,
data_pages(db_id(), o.id, 0) * (@@maxpagesize/1024) AS kbs
from sysobjects o
where type = 'U'
order by table_name , kbs

这是抛出错误

select top 10 data_pages(db_id(), o.id, 0) * (@@maxpagesize/1024) AS kbs ,
convert(varchar(30),o.name) AS table_name,
row_count(db_id(), o.id) AS row_count,
data_pages(db_id(), o.id, 0) AS pages
from sysobjects o
where type = 'U'
order by  kbs , table_name

Answer 1

此查询适用于我的 ASE 16.0 系统：

select top 10 convert(varchar(30),o.name) AS table_name,
row_count(db_id(), o.id) AS row_count,
data_pages(db_id(), o.id, 0) AS pages,
data_pages(db_id(), o.id, 0) * (@@maxpagesize/1024) AS kbs
from sysobjects o
where type = 'U'
order by kbs DESC, table_name ASC

如何 select 最大前 10 (n) 行的大小？

how to select max top 10 (n) rows with there size?

sybase

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