只有驼峰键的对象类型

Question

有没有办法编写强制对象键采用驼峰式命名的类型或接口？

type CamelCaseObject = // ... ?

const myObject: CamelCaseObject;
myObject.camelCaseKey; // Ok
myObject.not_camel_case_key; // Not ok.

或者一个接口也可以。

interface ICamelCaseObject = {
  [key: string /* that matches camelCase */]: OtherType;
}

const myObject: ICamelCaseObject;
myObject.camelCaseKey; // Ok
myObject.not_camel_case_key; // Not ok.

Answer 1

好吧，您不能使用静态类型强制字符串是驼峰式大小写。但是，您可以强制所有属性名称不包含下划线，这将不允许蛇形大小写：

type OtherType = string;

interface ICamelCaseObject {
    [key: string /* that matches camelCase */]: OtherType;
    [K: `${string}_${string}`]: never; // matches snake case and forces never
}

// this works
const foo: ICamelCaseObject = {
    heyYou: "boi",
};

// this fails
const foo2: ICamelCaseObject = {
    oh_noes: "hey", // Type 'string' is not assignable to type 'never'.
};

TypeScript Playground Link

只有驼峰键的对象类型

Type of object with only camel case keys

typescript

typescript-typings