使用 Google Apps 脚本循环遍历数据集时如何构建二维数组？

Question

因此，数据如下所示：

下面的代码像这样构建一个数组：

[1,"Forro","Teste Molde",2,"36 + 38 + 40 + 42",4,8,"Não Espelhado","Tecido/Pé","Obs",2,"Tag Código Produto","Molde 2",5,"36 + 40",2,10,"Sim","Tecido/Pé2","Obs 2"]

但是需要这样，从Risco开始，到Obs结束：

[
 [1,"Forno","Teste Molde",2,"36 + 38 + 40 + 42",4,8,"Não Espelhado","Tecido/Pé","Obs"],
 [2,"Tag Código Produto","Molde 2",5,"36 + 40",2,10,"Sim","Tecido/Pé2","Obs 2"]
]

这是我正在研究的代码：

function salvarCorte(status) {
  if (status != '') {
    const dadosCorte = sheetCorte.getRange(1, 1, sheetCorte.getLastRow(), sheetCorte.getLastColumn()).getValues();
    let outerArray= [];
    var innerArray = [];
    const parametrosRisco = ["Risco", "Matéria Prima", "Molde", "Tamanho", "Grade", "Consumo Unit.", "Espelhado", "Tecido/Pé", "Obs", "Qtd/Peças"];
    let startedArray = false
    for (let r = 0; r < dadosCorte.length; r++) {
      if (dadosCorte[r][0] == 'Risco') {
        startedArray = true
      }
      if (startedArray == true) {
        if (parametrosRisco.indexOf(dadosCorte[r][0]) > -1) {
          innerArray .push(dadosCorte[r][1]);
        }
        if (parametrosRisco.indexOf(dadosCorte[r][2]) > -1) {
          innerArray .push(dadosCorte[r][3]);
        }
        if (dadosCorte[r][0] == 'Obs') {
          startedArray = false;
        }
      }
    }
    outerArray.concat(innerArray )
  }
}

感谢您的帮助！

Answer 1

当我看到您的脚本时，来自 outerArray.concat(innerArray )，我认为您当前的价值无法复制。所以，我担心您的显示脚本可能与复制您的显示第一个值的脚本不同。

那么，在您的情况下，下面的示例脚本怎么样？

示例脚本：

var sheetCorte = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("Sheet"); // Please set the sheet name.
const dadosCorte = sheetCorte.getRange(1, 1, sheetCorte.getLastRow(), sheetCorte.getLastColumn()).getValues();
const parametrosRisco = ["Risco", "Matéria Prima", "Molde", "Tamanho", "Grade", "Qtd/Peças", "Consumo Unit.", "Espelhado", "Tecido/Pé", "Obs"];
const obj = dadosCorte.reduce((o, [a, b, c, d]) => {
  if (a && parametrosRisco.includes(a)) o[a] = o[a] ? [...o[a], b] : [b];
  if (c && parametrosRisco.includes(c)) o[c] = o[c] ? [...o[c], d] : [d];
  return o;
}, {});
const v = parametrosRisco.map(e => obj[e]);
const res = v[0].map((_, c) => v.map(r => r[c]));
console.log(res)

在此示例中，首先使用 parametrosRisco 创建一个对象。并且，使用 parametrosRisco，从对象中检索您的预期值。

参考文献：

Answer 2

逐行构建二维数组

function myfunk() {
  const sh = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("Sheet0"); // Please set the sheet name.
  const vs = sh.getRange(1, 1, sh.getLastRow(), sh.getLastColumn()).getValues();
  const headers = ["Section", "Name1", "Name2", "Name3", "Name4", "Name5", "Name6", "Name7", "Name8", "Name9"];
  const obj = vs.reduce((o, [a, b, c, d], i) => {
    if (a && headers.includes(a)) {
      o.row.push(b);
      if(o.row.length == headers.length) {
        o.r.push(o.row);
        o.row = [];
      }
    }
    if (c && headers.includes(c)) {
      o.row.push(d);
    }
    return o;
  }, { row: [],r: [] });
  console.log(obj.r);
}

Execution log
11:30:09 PM Notice  Execution started
11:30:10 PM Info    [ [ 1,
    'Value11',
    'Value2',
    'Value3',
    'Value4',
    'Value5',
    'Value6',
    'Value7',
    'Value8',
    'Value19' ],
  [ 2,
    'Value21',
    'Value2',
    'Value3',
    'Value4',
    'Value5',
    'Value6',
    'Value7',
    'Value8',
    'Value29' ],
  [ 3,
    'Value31',
    'Value2',
    'Value3',
    'Value4',
    'Value5',
    'Value6',
    'Value7',
    'Value8',
    'Value39' ] ]
11:30:11 PM Notice  Execution completed

我的Sheet:

Section	1
Name1	Value11
Name2	Value2
Name3	Value3
Name4	Value4	Name5	Value5
Name6	Value6
Name7	Value7
Name8	Value8
Name9	Value19


Section	2
Name1	Value21
Name2	Value2
Name3	Value3
Name4	Value4	Name5	Value5
Name6	Value6
Name7	Value7
Name8	Value8
Name9	Value29

Section	3
Name1	Value31
Name2	Value2
Name3	Value3
Name4	Value4	Name5	Value5
Name6	Value6
Name7	Value7
Name8	Value8
Name9	Value39

使用 Google Apps 脚本循环遍历数据集时如何构建二维数组？

How to build 2D array when looping through sets of data using Google Apps Script?

javascript

google-sheets

google-apps-script

示例脚本：

参考文献：

逐行构建二维数组