如何创建以编程方式扩展联合类型 class 的泛型

Question

我有以下代码：

const events = {
  a: ['event1' as const, 'event2' as const],
  b: ['event3' as const, 'event4' as const],
};

class SomeClass<
  T extends AnotherClass<typeof events[keyof typeof events][number]>
> {}

T 将是：T in SomeClass<T extends AnotherClass<"event1" | "event2" | "event3" | "event4">>

但我想看看：T in SomeClass<T extends AnotherClass<"event1" | "event2"> | AnotherClass<"event3" | "event4">>

除了像这样列出所有选项之外，是否有更好的方法来实现此结果：

class SomeClass<
  T extends
    | AnotherClass<typeof events.a[number]>
    | AnotherClass<typeof events.b[number]>
> {}

Answer 1

我们可以映射events的属性：

class SomeClass3<
  T extends {
    [K in keyof typeof events]: AnotherClass<typeof events[K][number]>
  }[keyof typeof events]
> {}

Sandbox

如何创建以编程方式扩展联合类型 class 的泛型

How to create generic that extends union type of class programaticaly

typescript

typescript-generics