如何 append/concat 逗号分隔值上逗号后的字符串？

Question

我有一列存储用逗号分隔的值。是这样的：

+--------------+-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| breakfast_id | breakfast_english_menu                                                                                                                                                                                                                    |
+--------------+-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
|            1 | Canned Orange Juice- Can of 5 to 7 oz, Oatmeal- ½ T, Almonds - (12 almonds), Milk with Coffee or Milk with Chocolate (1T.) (Only one)                                                                                                     |
+--------------+-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+

所以我想在 'new value' 开头的每个逗号后添加一个字符串。就像

+--------------+-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| breakfast_id | breakfast_english_menu                                                                                                                                                                                                                    |
+--------------+-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
|            1 | Canned Orange Juice- Can of 5 to 7 oz, [HI]Oatmeal- ½ T, [HI]Almonds - (12 almonds), [HI]Milk with Coffee or Milk with Chocolate (1T.) (Only one)                                                                                                     |
+--------------+-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+

欢迎任何帮助或提示。

Answer 1

因为你只有一个简单的模式，所以使用 REPLACE

SELECT REPLACE('ned Orange Juice- Can of 5 to 7 oz, Oatmeal- ½ T, Almonds - (12 almonds), Milk with Coffee or Milk with Chocolate (1T.) (Only one)',', ',', [HI]')

| REPLACE('ned Orange Juice- Can of 5 to 7 oz, Oatmeal- ½ T, Almonds - (12 almonds), Milk with Coffee or Milk with Chocolate (1T.) (Only one)',', ',', [HI]') |
| :----------------------------------------------------------------------------------------------------------------------------------------------------------- |
| ned Orange Juice- Can of 5 to 7 oz, [HI]Oatmeal- ½ T, [HI]Almonds - (12 almonds), [HI]Milk with Coffee or Milk with Chocolate (1T.) (Only one)              |

db<>fiddle here

对于更复杂的模式，您可以使用正则表达式来查找和替换。

如果需要，您可以将 REPLACE 命令嵌套在另一个命令中以替换多个 strintg

Answer 2

如果您想更改数据库中的值，您可以使用此查询：

UPDATE [MyTable] SET  
[breakfast_english_menu]=Replace([breakfast_english_menu],',',', [HI]')
Where [breakfast_id]=1

如何 append/concat 逗号分隔值上逗号后的字符串？

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