获取最大工作时间的日期

Question

Tables: 员工（ID，姓名） EmployeeHours ( EmployeeID ,Date, Hours )

这是我的要求：

Write a sql for following results for a year EmployeeID , TotalHoursWorked , Date and Hours ( Date and Hours when Employee worked most )

我写了以下查询：

select e.id, e.name, sum(eh.hours) as totalHoursWorked, max(hours) hour
from shoplist.emp e, shoplist.empHours eh where e.id = eh.empId 
group by eh.empId;

我可以使用 maxHour 获取 ID、名称、totalHoursWorked，但我对如何获取最长工作时间的日期感到有点困惑。有人可以帮我解决这个问题吗？

示例数据：

Emp Table

id, name
'1','akhil'
'2','preethi'
'3','gopi'

工作时间Table

id, empId, hours, date
'1','1','3','2022-05-12'
'2','1','5','2022-05-11'
'3','1','4','2022-05-10'
'4','2','2','2022-05-12'
'5','2','4','2022-05-10'
'6','3','3','2022-05-09'
'7','3','5','2022-05-08'

预计

id, name, totalHoursWorked, maxHours, maxHourDate
'1','akhil','12','5','2022-05-12'
'2','preethi','6','4','2022-05-12'
'3','gopi','8','5','2022-05-09'

Answer 1

您可以使用您的查询结果与原始查询结果合并 table

  select distinct eh1.empId, eh1.date, t.hours, t.name, t.totalHoursWorked 
  from shoplist.empHours eh1 inner join ( 
    select e.id, e.name, sum(eh.hours) as totalHoursWorked, max(eh.hours) hours 
    from shoplist.emp e 
    inner join shoplist.empHours eh on e.id = eh.empId group by eh.empId 
  ) t on t.id = eh1.empId AND t.hours = eh1.hours

对于具有相同小时数的多个日期的相同用途，您可以通过这种方式选择最大值或最小值

  select  eh1.empId, max(eh1.date), t.hours, t.name, t.totalHoursWorked 
  from shoplist.empHours eh1 inner join ( 
    select e.id, e.name, sum(eh.hours) as totalHoursWorked, max(eh.hours) hours 
    from shoplist.emp e 
    inner join shoplist.empHours eh on e.id = eh.empId group by eh.empId 
  ) t on t.id = eh1.empId AND t.hours = eh1.hours
  group by eh1.empId

获取最大工作时间的日期

Get date of max hours worked

mysql