如何在 PHP 中将一个数组设置为另一个数组的值？

Question

我有以下数组：

Array
(
    [0] => James
    [1] => Mike
    [2] => Liam
    [3] => Shantel
    [4] => Harry
)
Array
(
    [0] => Green
    [1] => Blue
    [2] => Yellow
    [3] => Purple
    [4] => Red
)

如何将这两个数组放入 JSON 对象中？

所以这应该是预期的输出：

{"James":"Green","Mike":"Blue","Liam":"Yellow","Shantel":"Purple"}

这是我尝试做的，但我得到了完全不同的输出：

$final = array();
$names = ['James', 'Mike', 'Liam', 'Shantel', 'Harry']
$colors = ['Green', 'Blue', 'Yellow', 'Purple', 'Red']


for ($i = 0; $i <= 4; $i++) {
    $final[] = array_push($final, $names[$i], $colors[$i]);
}

我做错了什么？

Answer 1

您想将 $final 的特定键设置为特定值。因此，与其使用 array_push（或 $final[]），它只是将一个值添加到索引数组，不如定义关联数组 $final 的 key/value，例如：

$final[$names[$i]] = $colors[$i];

$final = array();
$names = ['James', 'Mike', 'Liam', 'Shantel', 'Harry'];
$colors = ['Green', 'Blue', 'Yellow', 'Purple', 'Red'];


foreach($names as $i => $key) {
    $final[$key] = $colors[$i];
}

https://3v4l.org/cgHtD

的工作示例

Answer 2

尝试array_combine()

$a = ["James", "Mike", "Liam", "Shantel", "Harry"];

$b = ["Green", "Blue", "Yellow", "Purple", "Red"];

$c = array_combine($a, $b);


print_r($c);

echo json_encode($c);

输出：

Array
(
    [James] => Green
    [Mike] => Blue
    [Liam] => Yellow
    [Shantel] => Purple
    [Harry] => Red
)
{"James":"Green","Mike":"Blue","Liam":"Yellow","Shantel":"Purple","Harry":"Red"}

如何在 PHP 中将一个数组设置为另一个数组的值？

How can I set one array as a value of another array in PHP?

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