根据条件减去行

Subtracting rows based on condition

假设我有一个 table 看起来像这样:

OrderNumber  OrderType
1            D          
1            D          
1            R 
2            D
2            R
3            D          
3            D          
3            D
3            R          
3            R

结果应该是:

OrderNumber  OrderType
1            D          
3            D

在这里,R 表示从订单中删除一行。我们在第一个示例中看到我们有 2 个 D 和 1 个 R,因此我们删除一个 D 并用 1 个 D 替换。在 SQL 中有没有办法做到这一点?

您可以使用window功能。这是 sqlite 语法,但 mysql 应该相当接近。

select A.OrderNumber,A.OrderType

from (select OrderNumber,OrderType,row_number() over(partition by OrderNumber) as RN 
from b where OrderType='D') A
left join

(select sum(case when OrderType='R' then 1 else 0 end) as cnt,OrderNumber
from b group by OrderNumber) B
on A.OrderNumber=B.OrderNumber
where A.rn>B.cnt;

如果你的mysql版本支持cte和window函数,我们可以尝试使用ROW_NUMBERwindow函数为每个OrderNumber制作行号OrderType

然后使用EXISTS子查询判断OrderType = D行号需要大于来自R.

的最大行号
with cte as (
  SELECT *,
         ROW_NUMBER() OVER(PARTITION BY OrderNumber,OrderType) rn,
         COUNT(*) OVER(PARTITION BY OrderNumber,OrderType) cnt
  FROM T
)
SELECT c1.OrderNumber,
       c1.OrderType 
FROM cte c1
WHERE EXISTS (
   SELECT 1 
   FROM cte c2
   WHERE c1.OrderNumber = c2.OrderNumber 
   AND c2.OrderType = 'R'
   AND c1.rn > c2.cnt
)
AND c1.OrderType = 'D'

sqlfiddle