如何用 python pandas 替换部分字符串?

How to replace part of string with python pandas?

我在替换 Pandas 中的部分字符串时遇到问题。

我有一个这样的网站的链接列表(例如):

https://whosebug.com/questions
https://whosebug.com/some_page
https://whosebug.com/about

我想用 link/ 替换 https://whosebug.com/

应该是这样的:

link/questions
link/some_page
link/about

我试过类似的方法,但它替换了整个字符串:

df.loc[df['links'].str.contains('https://whosebug.com/'), 'links'] = 'link/'

links 是列的名称

我该怎么做?

提前致谢。

只要 URL 一致,这应该可以满足您的需求。

data = {
    'Column1' : ['https://whosebug.com/questions', 'https://whosebug.com/another', 'https://whosebug.com/last']
}

df = pd.DataFrame(data)
df['Column1'] = df['Column1'].apply(lambda x : 'Link/' + x.split('/')[-1])
df
df.loc[df['links'].str.contains('https://whosebug.com/'), 'links'] = \
    'link/' + df[0].str.extract('.*/(.*)') 

                                     0           links
0  https://whosebug.com/questions  link/questions
1  https://whosebug.com/some_page  link/some_page
2      https://whosebug.com/about      link/about

你需要 .str.replace 作业

df.loc[df['links'].str.contains('https://whosebug.com/'), 'links'] = df['links'].str.replace('https://whosebug.com/', 'link/')
print(df)

                             links
0                   link/questions
1                   link/some_page
2                       link/about
3  https://Whosebug/questions