如何计算每个会话的员工总工作时间

Question

我需要显示一天中每个会话的员工登录和注销时间，并计算总工作时间。如果员工登录和注销多次，则应显示每次会话和总数。

我的 table 看起来像这样

Id	EmpId	LocationId	LogDate	AccessType	OutType
1	4545_1	4545	2022-05-25 16:27:41.217	1	NULL
2	4545_1	4545	2022-05-25 17:27:26.673	2	1
4	4545_1	4545	2022-05-25 17:31:30.333	1	NULL
5	4545_1	4545	2022-05-25 19:31:38.973	2	1
6	1212_8	1212	2022-05-26 10:21:38.973	1	NULL
6	1212_8	1212	2022-05-26 12:21:38.973	2	2

这里访问类型 1=IN 2=OUT OutType 1=注销 2=会话退出

我想要这样的输出

EmpId	LocationId	SessionStart	SessionEnd	Hours
4545_1	4545	2022-05-25 16:27:41.217	2022-05-25 17:27:26.673	1:00
4545_1	4545	2022-05-25 17:31:30.333	2022-05-25 19:31:38.973	2:00
1212_8	1212	2022-05-26 10:21:38.973	2022-05-26 12:21:38.973	2:00

这是我试过的


select[EmpId],
[LocationId],
ShiftDate, 
SessionStartTime, 
SessionEndTime
, Total_Time = right(concat('0', Total_Time / 3600), 2) + ':' + right(concat('0', Total_Time % 3600 / 60), 2)  
from (
    select
       [EmpId],[LocationId], ShiftDate = cast(min(LogDate) as date)
        , SessionStartTime = min(LogDate)
        , SessionEndTime = max(LogDate)
        , Total_Time = sum(ss)
      
    from (
        select
            *, ss = datediff(ss, LogDate, lead(LogDate) over (partition by [EmpId], grp order by LogDate))
        from (
            select
                *, grp = sum(diff) over (partition by [EmpId] order by LogDate)
            from (
                select
                    *, diff = iif(datediff(mi, lag(LogDate) over (partition by [EmpId] order by LogDate), LogDate) > 300 and [AccessType] = 1, 1, 0)
                from
                    [tblEmployeeAttendance]  where cast(LogDate as date) >= '2022-05-25'  and cast(LogDate as date) <= '2022-05-26'
            ) t
        ) t
    ) t 
    group by [EmpId],[LocationId], grp) t

我得到了这样的结果

EmpId	LocationId	SessionStart	SessionEnd	Hours
4545_1	4545	2022-05-25 16:27:41.217	2022-05-25 19:31:38.973	3:00
1212_8	1212	2022-05-26 10:21:38.973	2022-05-26 12:21:38.973	2:00

这里的问题是我在一行中只获得一天的最小登录和最大注销。但是我需要用户当天的每个登录和注销会话以及每个会话的总数。

我请人帮忙。

Answer 1

您可以使用外部应用来完成此操作。
不知道OutType有什么用，和AccessType有什么区别。您没有解释那个或任何其他逻辑，所以我只是假设它应该适用于 AccessType。
如果不是这种情况，您可以轻松调整下面子查询中的逻辑。

select e.EmpId,
       e.LocationID,
       e.logdate as SessionStart,
       d.logdate as SessionEnd,
       datediff(hour, e.logdate, d.logdate) as Hours
from   emp e
  outer apply ( select top 1 emp.logdate
                from   emp
                where  emp.empid = e.empid
                and    emp.accesstype = 2
                and    emp.logdate > e.logdate
                order by emp.logdate
              ) d
where  e.accesstype = 1

查看DBFiddle这里

结果

EmpId	LocationID	SessionStart	SessionEnd	Hours
4545_1	4545	2022-05-25 16:27:41.217	2022-05-25 17:27:26.673	1
4545_1	4545	2022-05-25 17:31:30.333	2022-05-25 19:31:38.973	2
1212_8	1212	2022-05-26 10:21:38.973	2022-05-26 12:21:38.973	2

如何计算每个会话的员工总工作时间

How to calculate Total working hours of employee by each session

sql

sql-server