我需要将数据保存并加载到 JSON 文件，我已经这样做了，但我知道我遇到了问题

Question

我正在使用它来将文件中的信息加载到收据目录中。

receipts = {}

with open("receipts.json","r") as file_receipts:
    load_receipts = json.load(file_receipts)
    receipts = load_receipts
    file_receipts.close()

当我创建了json文件时它可以工作，并且里面有信息......但是当文件没有信息时，程序会崩溃，所以我怎样才能避免程序崩溃该程序是运行第一次？

另外当json文件有信息时，它有这样的东西：

{"Josh": {"n_orders": 2, "id0": {"combo_1": {"dish": "Personal Pizza", "drink": "Soda", "order": "French Fries", "price": "8", "id": "combo"}}, "id1": {"soda": {"order": "Soda", "price": "2", "id": "order"}}}, "Mary": {"n_orders": 2, "id0": {"pizza": {"order": "Personal Pizza", "price": "4", "id": "dish"}}, "id1": {"soda": {"order": "Soda", "price": "2", "id": "order"}}}}

Answer 1

使用尝试除外：

import os

receipts = {}

if os.path.exist("receipts.json"):
    with open("receipts.json","r") as file_receipts:
        try:
           load_receipts = json.load(file_receipts)
           receipts = load_receipts
        except:
           pass # error handling
        # file_receipts.close() # this is not needed inside "with"

Answer 2

捕捉FileNotFoundError异常，像这样：

try:
    with open("receipts.json","r") as file_receipts:
        receipts = json.load(file_receipts)
except FileNotFoundError:
    receipts = {}
    print("File doesn't exist yet.")

我稍微简化了你的代码，你不需要关闭使用 with 打开的文件，因为当执行离开 with 时它们会自动关闭阻止。

我需要将数据保存并加载到 JSON 文件，我已经这样做了，但我知道我遇到了问题

I need to save and load data to a JSON file, and I already did it, but know I have a problem

python