如何通过分析获得正确的摘要？

Question

如果特定 invoice_code 出现在 invoice_detail 中，我想从 cust_detail table 中获取摘要数字。

在这个例子中，我只想报告批次 10 和 20 的 cust_detail 摘要，因为它们是带有 invoice_code='9999' 的批次。但是 invoice_detail table 中的重复歪曲了我的数字。

with
  invoice_detail as
  (
    select '10' as invoice_batch, '9999' as invoice_code from dual union all 
    select '10' as invoice_batch, '9999' as invoice_code from dual union all
    select '20' as invoice_batch, '1111' as invoice_code from dual union all
    select '30' as invoice_batch, '9999' as invoice_code from dual
  ),
  cust_detail as
  (
    select '1' as cust_id, '10' as invoice_batch, 40 as points_paid, 30 as points_earned, 30 as points_delivered from dual union all
    select '1' as cust_id, '20' as invoice_batch, 10 as points_paid, 10 as points_earned, 10 as points_delivered from dual union all
    select '1' as cust_id, '30' as invoice_batch, 20 as points_paid, 15 as points_earned,  5 as points_delivered from dual
  )
select cust_id, 
       sum(points_paid) over (partition by  c.invoice_batch
                                  order by cust_id) batch_total
  from cust_detail c
 inner join invoice_detail i on c.invoice_batch=i.invoice_batch
 where i.invoice_code = '9999';

期望的结果：

 CUST_ID   PAID   EARNED   DELIVERED   TOT_PAID   TOT_EARNED   TOT_DELIVERED
--------- ------ -------- ----------- ---------- ------------ ---------------
 1         40     30       30          60         45           40      
 1         20     15       5           60         45           40

Answer 1

我不确定您想要的结果与您的查询有什么关系。但是，我希望您的查询看起来更像这样：

select cust_id, 
       sum(points_paid) over (partition by cust_id) as batch_total
from cust_detail c inner join
     invoice_detail i
     on c.invoice_batch=i.invoice_batch
where i.invoice_code = '9999' ;

Answer 2

您可以在加入之前使用 distinct 从 invoice_detail 中删除重复项：

with invoice_detail as
(
select '10' as invoice_batch, '9999' as invoice_code from dual union all 
select '10' as invoice_batch, '9999' as invoice_code from dual union all
select '20' as invoice_batch, '1111' as invoice_code from dual union all
select '30' as invoice_batch, '9999' as invoice_code from dual
),
cust_detail as
(
select '1' as cust_id, '10' as invoice_batch, 40 as points_paid, 30 as points_earned, 30 as points_delivered from dual union all
select '1' as cust_id, '20' as invoice_batch, 10 as points_paid, 10 as points_earned, 10 as points_delivered from dual union all
select '1' as cust_id, '30' as invoice_batch, 20 as points_paid, 15 as points_earned,  5  as points_delivered from dual
)
select cust_id
            ,points_paid
            ,points_earned
            ,points_delivered
            ,sum(points_paid) over (partition by c.cust_id) as tot_paid
            ,sum(points_earned) over (partition by c.cust_id) as tot_earned
            ,sum(points_delivered) over (partition by c.cust_id) as tot_delivered           
from cust_detail c 
join (select distinct * from invoice_detail) i
     on c.invoice_batch=i.invoice_batch
where i.invoice_code = '9999';

请注意，摘要包括批次 10 和 30，因为批次 20 具有 invoice_code='1111'。

SQL Fiddle

如何通过分析获得正确的摘要？

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