减去相同的两个日期时如何计算为 1 天

Question

这是我计算两个给定日期之间差异的代码

days = datetime.strptime(todate, "%Y-%m-%d") - datetime.strptime(fromdate, "%Y-%m-%d")
print days

它工作正常。但是，问题是当给定两个相同的日期时，即 todate = 2015-07-31, fromdate = 2015-07-31，它会将其计算为 0 天。我希望如果 todate 和 fromdate 相同，则计算应该是 1 而不是 0。

Answer 1

可能使用布尔运算符：

from datetime import datetime, timedelta

days = datetime.strptime(todate, "%Y-%m-%d") - datetime.strptime(fromdate, "%Y-%m-%d")
days = days or timedelta(days=1)

Answer 2

如何使用max来限制return值不低于一天

days = max(timedelta(days=1),
           datetime.strptime(todate, "%Y-%m-%d") -
           datetime.strptime(fromdate, "%Y-%m-%d"))

>>> fromdate = '2015-07-31'
>>> todate = '2015-07-31'
>>> days = max(timedelta(days=1),
...            datetime.strptime(todate, "%Y-%m-%d") -
...            datetime.strptime(fromdate, "%Y-%m-%d"))
>>> days
datetime.timedelta(1)

减去相同的两个日期时如何计算为 1 天

How do i make the calculation as 1 day when subtracting same two dates

python

date

django-views