guzzle `http_errors` 将错误从 500 更改为 404

Question

我有一个正在测试的函数，假设 return 错误 500 但在将 'http_errors' => 'false' 添加到 put 定义后，returned 错误从 500 变为404. 这是我的职能：

public function testApiAd_updateWithIllegalGroupId($adId) 
{
    $client = new Client(['base_uri' => self::$base_url]);
    try {
        $response = $client->put(self::$path.$adId, ['form_params' => [
          'name' => 'bellow content - guzzle testing',
          'description' => 'guzzle testing ad - demo',
          'group_id' => '999999999',
          ]]);
    } catch (Guzzle\Http\Exception\BadResponseException $e) {
        //Here i want to compare received error to 500
    }
}

现在这个函数将 return server error: 500 但它也会阻止 class 执行其余测试，我无法断言。我怎样才能在我的函数中使用 guzzle getStatusCode() 而得到错误 500 而不是我上面提到的 404

Answer 1

BadResponseException 包含原始请求和响应对象。所以你可以，catch 块下面的断言：

} catch (Guzzle\Http\Exception\BadResponseException $e) {
        //Here i want to compare received error to 500
        $responseCode = $e->getResponse()->getStatusCode();
        $this->assertEquals(500, $responseCode, "Server Error");
    }

更多信息in the doc

guzzle `http_errors` 将错误从 500 更改为 404

guzzle `http_errors` changes error from 500 to 404

php

phpunit

guzzle