oracle中的正则表达式获取从100.64.*.*到100.127.*.*的IP地址范围？
regular expression in oracle to get a range of ip address from 100.64.*.* to 100.127.*.*?
我想获取从 100.64.. 到 100.127..
的 IP 地址范围
如果我有 table 命名的 testIp 和名为 PRIVATE_IP_ADDR 的列，下面是存在的记录：
1) 100.63.22.55
2) 100.64.102.558
3) 100.123.22.12
4) 100.127.22.55
5) 100.128.221.55
6) 100.125.355.10
7) 100.64.102.254
要求：
1. 2nd part of ip should be from 64 to 127 range
2. 3rd part of ip should be from 0 to 255 range
3. 4th part of ip should be from 0 to 255 range
正则表达式应该选择下面的 ip 地址
3) 100.123.22.12
4) 100.127.22.55
7) 100.64.102.254
到目前为止我尝试过的是：
select * from testip where REGEXP_LIKE (PRIVATE_IP_ADDR , '^(100\.
(6[4-9]|[7-9][0-9]|1[0-2][0-7])\.
([0-1]?[0-9]?[0-9]|2[0-5][0-5])\.
([0-1]?[0-9]?[0-9]|2[0-5][0-5]))' ) ;
but when i tried the result is
2) 100.64.102.558
3) 100.123.22.12
4) 100.127.22.55
7) 100.64.102.254
i dont want the record
2)100.64.102.558
IPv4 地址的正则表达式
当然对于 IPv4 地址，您可以使用正则表达式并只选择第二组数字。
这里我使用转义字符 \d 作为数字。正则表达式中的 2 只是表示我们想要一组数字的第二次出现。
最后，我将值转换为数字并使用 between 运算符。
SCOTT@db>list
1 WITH t AS
2 (SELECT '100.127.22.55' ip_address FROM dual
3 UNION ALL
4 SELECT '100.66.22.55' FROM dual
5 UNION ALL
6 SELECT '100.123.22.12' FROM dual
7 UNION ALL
8 SELECT '100.63.22.55' FROM dual
9 )
10 SELECT *
11 FROM
12 (SELECT t.ip_address,
13 regexp_substr(t.ip_address, '^\d+',1,1) first_number,
14 to_number(regexp_substr(t.ip_address, '\d+',1,2)) second_number
15 FROM t
16 )
17 WHERE 1=1
18 AND first_number = '100'
19* AND second_number BETWEEN 66 AND 127
SCOTT@db>/
IP_ADDRESS FIRST_NUMBER SECOND_NUMBER
------------- ---------------------------------------------------- -------------
100.123.22.12 100 123
100.127.22.55 100 127
100.66.22.55 100 66
根据操作评论更新
采用 regexp_like 方法（并考虑如何更广泛地描述问题），解决方案如下。使用量词时需要非常小心，我发现使用锚点很有帮助：
SCOTT@db>WITH t AS
2 (SELECT '100.63.22.55' ip_address FROM dual
3 UNION ALL
4 SELECT '100.64.102.558' ip_address FROM dual
5 UNION ALL
6 SELECT '100.123.22.12' ip_address FROM dual
7 UNION ALL
8 SELECT '100.127.22.55' ip_address FROM dual
9 UNION ALL
10 SELECT '100.128.221.55' ip_address FROM dual
11 UNION ALL
12 SELECT '100.125.355.10' ip_address FROM dual
13 UNION ALL
14 SELECT '100.64.102.254' ip_address FROM dual
15 )
16 SELECT *
17 FROM t
18 WHERE REGEXP_LIKE (t.ip_address , '^100\.(6[4-9]|[7-9][0-9]|1[0-2][0-7])(\.([1-9][0-9]?|1[0-9][0-9]|2([0-4][0-9]|5[0-5]))){2}$')
19 /
IP_ADDRESS
--------------
100.123.22.12
100.127.22.55
100.64.102.254
我想获取从 100.64.. 到 100.127..
的 IP 地址范围如果我有 table 命名的 testIp 和名为 PRIVATE_IP_ADDR 的列，下面是存在的记录：
1) 100.63.22.55
2) 100.64.102.558
3) 100.123.22.12
4) 100.127.22.55
5) 100.128.221.55
6) 100.125.355.10
7) 100.64.102.254
要求：
1. 2nd part of ip should be from 64 to 127 range
2. 3rd part of ip should be from 0 to 255 range
3. 4th part of ip should be from 0 to 255 range
正则表达式应该选择下面的 ip 地址
3) 100.123.22.12
4) 100.127.22.55
7) 100.64.102.254
到目前为止我尝试过的是：
select * from testip where REGEXP_LIKE (PRIVATE_IP_ADDR , '^(100\.
(6[4-9]|[7-9][0-9]|1[0-2][0-7])\.
([0-1]?[0-9]?[0-9]|2[0-5][0-5])\.
([0-1]?[0-9]?[0-9]|2[0-5][0-5]))' ) ;
but when i tried the result is
2) 100.64.102.558
3) 100.123.22.12
4) 100.127.22.55
7) 100.64.102.254
i dont want the record
2)100.64.102.558
IPv4 地址的正则表达式
当然对于 IPv4 地址，您可以使用正则表达式并只选择第二组数字。
这里我使用转义字符 \d 作为数字。正则表达式中的 2 只是表示我们想要一组数字的第二次出现。
最后，我将值转换为数字并使用 between 运算符。
SCOTT@db>list
1 WITH t AS
2 (SELECT '100.127.22.55' ip_address FROM dual
3 UNION ALL
4 SELECT '100.66.22.55' FROM dual
5 UNION ALL
6 SELECT '100.123.22.12' FROM dual
7 UNION ALL
8 SELECT '100.63.22.55' FROM dual
9 )
10 SELECT *
11 FROM
12 (SELECT t.ip_address,
13 regexp_substr(t.ip_address, '^\d+',1,1) first_number,
14 to_number(regexp_substr(t.ip_address, '\d+',1,2)) second_number
15 FROM t
16 )
17 WHERE 1=1
18 AND first_number = '100'
19* AND second_number BETWEEN 66 AND 127
SCOTT@db>/
IP_ADDRESS FIRST_NUMBER SECOND_NUMBER
------------- ---------------------------------------------------- -------------
100.123.22.12 100 123
100.127.22.55 100 127
100.66.22.55 100 66
根据操作评论更新
采用 regexp_like 方法（并考虑如何更广泛地描述问题），解决方案如下。使用量词时需要非常小心，我发现使用锚点很有帮助：
SCOTT@db>WITH t AS
2 (SELECT '100.63.22.55' ip_address FROM dual
3 UNION ALL
4 SELECT '100.64.102.558' ip_address FROM dual
5 UNION ALL
6 SELECT '100.123.22.12' ip_address FROM dual
7 UNION ALL
8 SELECT '100.127.22.55' ip_address FROM dual
9 UNION ALL
10 SELECT '100.128.221.55' ip_address FROM dual
11 UNION ALL
12 SELECT '100.125.355.10' ip_address FROM dual
13 UNION ALL
14 SELECT '100.64.102.254' ip_address FROM dual
15 )
16 SELECT *
17 FROM t
18 WHERE REGEXP_LIKE (t.ip_address , '^100\.(6[4-9]|[7-9][0-9]|1[0-2][0-7])(\.([1-9][0-9]?|1[0-9][0-9]|2([0-4][0-9]|5[0-5]))){2}$')
19 /
IP_ADDRESS
--------------
100.123.22.12
100.127.22.55
100.64.102.254