为什么 try and catch 不起作用？

Question

我正在尝试制作一个程序，告诉人们他们是否可以乘坐过山车。只要输入有效，它就会工作，但我希望它显示一条消息，说明如果用户输入其他内容则重试。我尝试使用 try and catch，但它仍然显示错误（NumberFormat 异常）。感谢任何帮助，谢谢。

private void btnCalculateActionPerformed(java.awt.event.ActionEvent evt) {                                             
    String strHeight, strBackTrouble, strHeartTrouble;
    int intHeight;

    strHeight = txtInputHeight.getText();
    strBackTrouble = txtInputBackTrouble.getText();
    strHeartTrouble = txtInputHeartTrouble.getText();

    intHeight = Integer.parseInt(strHeight);

    try {
        if (intHeight < 188 || intHeight > 122) {
            if (strBackTrouble.equals("N") || strBackTrouble.equals("n") || strHeartTrouble.equals("N") || strHeartTrouble.equals("n")) {
                    txtOutput.setText("It is OK for you to ride this roller coaster. Have fun!");
            }
        } else  if (strBackTrouble.equals("Y") || strBackTrouble.equals("y") || strHeartTrouble.equals("Y") || strHeartTrouble.equals("y")) {
                txtOutput.setText("Sorry, it is not safe for you to ride this rollercoaster");
            }

    } catch (Exception e) {
        txtOutput.setText("You entered invalid input, please try again");
    }

}

Answer 1

intHeight = Integer.parseInt(strHeight);

抛出不在 catch 块中的异常。

Answer 2

try {
    intHeight = Integer.parseInt(strHeight);
    if (intHeight < 188 || intHeight > 122) {
        if (strBackTrouble.equals("N") || strBackTrouble.equals("n") || strHeartTrouble.equals("N") || strHeartTrouble.equals("n")) {
                txtOutput.setText("It is OK for you to ride this roller coaster. Have fun!");
        }
    } else  if (strBackTrouble.equals("Y") || strBackTrouble.equals("y") || strHeartTrouble.equals("Y") || strHeartTrouble.equals("y")) {
            txtOutput.setText("Sorry, it is not safe for you to ride this rollercoaster");
        }

} 
catch(NumberFormatException e) {
    txtOutput.setText("You entered invalid number, please try again");
}
catch( Exception e) {
    txtOutput.setText("You entered invalid input, please try again");
}

java 7:

try {
    intHeight = Integer.parseInt(strHeight);
    if (intHeight < 188 || intHeight > 122) {
        if (strBackTrouble.equals("N") || strBackTrouble.equals("n") || strHeartTrouble.equals("N") || strHeartTrouble.equals("n")) {
                txtOutput.setText("It is OK for you to ride this roller coaster. Have fun!");
        }
    } else  if (strBackTrouble.equals("Y") || strBackTrouble.equals("y") || strHeartTrouble.equals("Y") || strHeartTrouble.equals("y")) {
            txtOutput.setText("Sorry, it is not safe for you to ride this rollercoaster");
        }

} catch (NumberFormatException e | Exception e) {
    txtOutput.setText("You entered invalid input, please try again");
}

为什么 try and catch 不起作用？

Why isn't the try and catch working?

java

try-catch