使用 Parse 从通讯录添加好友

Question

我正在构建一个应用程序，在登录 up/log 时，它将遍历用户地址簿，获取 phone 号码，检查 phone 号码列Parse 上的用户 class，如果他们不是朋友，则添加他们。

我在 AddressBookHelper.swift 中有一个函数可以帮助获取 phone 个数字：

class AddressBookHelper: NSObject {

let addressBook = AFAddressBookManager()

static var addressBookData = AFAddressBookManager.allContactsFromAddressBook()
static var contactsArray = [String]()

static func getContacts() -> [String] {

    var array = [String]()
    for contact in addressBookData{
        let phoneNumberArray = contact.numbers as! [String]
        for number in phoneNumberArray{ 
            array.append(number)  
        }
    }

    return array

}

}

然后在 ParseHelper.swift 我再次检查解析用户 class:

static func lookUpUserFromAddressBook(addressBook: [String], completionBlock: PFArrayResultBlock) {

    for numbers in addressBook{
        let query = User.query()
        query!.whereKey("telephone", equalTo:numbers)
        query!.findObjectsInBackgroundWithBlock(completionBlock)
    }

}

最后，当点击按钮时，我将用户添加为朋友，如果还不是朋友的话：

@IBAction func importContacts(sender: AnyObject) {

    ParseHelper.lookUpUserFromAddressBook(AddressBookHelper.getContacts())  {
        (results: [AnyObject]?, error: NSError?) -> Void in

        if error == nil {

            if let objects = results as? [PFObject] {
                for object in objects {

                    let userObject = object as! User
                    self.matchedUsers.append(userObject)

                    let query = PFQuery(className: "Friends")
                    query.includeKey("toUser")
                    query.whereKey("fromUser", equalTo: User.currentUser()!)
                    query.findObjectsInBackgroundWithBlock {
                        (objects: [AnyObject]?, error: NSError?) -> Void in

                        if error == nil {
                            if (objects!.count == 0) {

                                ParseHelper.addFollowRelationshipFromUser(fromUser: User.currentUser()!, toUser: userObject, completionBlock: { (success, error) -> Void in


                                    if success{
                                        self.performSegueWithIdentifier("skipped", sender: self)
                                    }
                                    else{
                                        print("Error: \(error!) \(error!.userInfo)")

                                    }
                                })
                            }
                            else{
                                self.performSegueWithIdentifier("skipped", sender: self)
                            }

                        } else {
                            print("Error: \(error) \(error!.userInfo)")
                        }

                    }
                }
            }
        }
        else {
            print("Error: \(error!) \(error!.userInfo)")
        }

    }

}

我这样做对吗？它有效，但代码似乎有点长。有更简单的方法吗？

提前致谢

Answer 1

你应该看看 PFQuery 的 whereKey:containedIn:。这将为您 return 列出其 phone 号码与您在数组中传递的任何号码匹配的所有用户。这将大大减少检索用户联系人所需执行的查询次数。

// Find users with any of these phone numbers
let numbers = ["1234567890", "1111111111", "222222222"]
query.whereKey("phoneNumber", containedIn: numbers)

来自 Parse iOS 开发人员指南： https://parse.com/docs/ios/guide#queries

If you want to retrieve objects matching several different values, you can use whereKey:containedIn:, providing an array of acceptable values. This is often useful to replace multiple queries with a single query.

您还可以使用 PFObject.saveAllInBackground() 在一个查询中创建所有跟随关系，该查询需要一组 PFObjects 来保存。

使用 Parse 从通讯录添加好友

Adding friends from address book using Parse

relation

addressbook

ios

parse-platform

swift