Python 元组问题

Question

我是 python 的新手，据我所知我收到了这个元组错误：

Traceback (most recent call last):
  File "/home/cambria/Main.py", line 10, in <module>
    main()
  File "/home/cambria/Main.py", line 5, in main
    respons3 = api.get_summoner_by_name('hi im gosan')
  File "/home/cambria/RiotAPI.py", line 31, in get_summoner_by_name
    return self._request(api_url)
  File "/home/cambria/RiotAPI.py", line 12, in _request
    for key, value in params.items():
AttributeError: 'tuple' object has no attribute 'items'

在

def _request(self, api_url, params=()):
        args = {'api_key': self.api_key}
        for key, value in params.items():
            if key not in args:
                args[key] = value
        response = requests.get(
            Consts.URL['base'].format(
                proxy=self.region,
                region=self.region,
                url=api_url
                ),
            params=args
            )
        print response.url
        return response.json()

这是我收到的唯一一个我真的不太了解的错误。这是我的参数没有 .items 的结果吗？或者我把它初始化为一个空字典？

编辑 1：尝试修改元组和项目，但运气不佳，我的错误消息如下

Traceback (most recent call last):
  File "/home/cambria/Desktop/api/Main.py", line 10, in <module>
    main()
  File "/home/cambria/Desktop/api/Main.py", line 5, in main
    respons3 = api.get_summoner_by_name('hi im gosan')
  File "/home/cambria/Desktop/api/RiotAPI.py", line 33, in get_summoner_by_name
    return self._request(api_url)
  File "/home/cambria/Desktop/api/RiotAPI.py", line 23, in _request
    params=args
  File "/home/cambria/.local/lib/python2.7/site-packages/requests/api.py", line 69, in get
    return request('get', url, params=params, **kwargs)
  File "/home/cambria/.local/lib/python2.7/site-packages/requests/api.py", line 50, in request
    response = session.request(method=method, url=url, **kwargs)
  File "/home/cambria/.local/lib/python2.7/site-packages/requests/sessions.py", line 465, in request
    resp = self.send(prep, **send_kwargs)
  File "/home/cambria/.local/lib/python2.7/site-packages/requests/sessions.py", line 573, in send
    r = adapter.send(request, **kwargs)
  File "/home/cambria/.local/lib/python2.7/site-packages/requests/adapters.py", line 415, in send
    raise ConnectionError(err, request=request)
ConnectionError: ('Connection aborted.', gaierror(-2, 'Name or service not known'))
>>>

据我所知和搜索，这是 python REQUESTS 未完全通过的结果？我的新代码如下，

  def _request(self, api_url, params=None): #edit
        if params is None:                  #edit
            params = {}                     #edit
        args = {'api_key': self.api_key}
        for key, value in params.items(): #remove?? since there is no .items()?
            if key not in args:
                args[key] = value
        response = requests.get(
            Consts.URL['base'].format(
                proxy=self.region,
                region=self.region,
                url=api_url
                ),
            params=args
            )
        print response.url
        return response.json()

Answer 1

你的代码期望 params 是一个字典 {}（或者有一个 .items 方法）。您传递了一个元组 ()。两者不等价。

默认设置params为None，需要时传a。

def _request(self, api_url, params=None):
    params = params if params is not None else {}
    ...

或者期待元组列表，而不是字典。

def _request(self, api_url, params=()):
    for key, value in params:
    ...

Answer 2

元组 () 没有名为 items 的方法。你可能会把它误认为是字典。按如下方式更改您的代码：

def _request(self, api_url, params=None):
    if params is None:
        params = {}
    ...

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