由于 SQL 语法错误

Question

我正在创建一个将图像上传到服务器的表单和另一个从数据库中检索图像的文件。

错误：

error in INSERT into 'images_tbl' ('images_path','submission_date') VALUES ('images/04-01-2015-1420392279.png','2015-01-04') == You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''images_tbl' ('images_path','submission_date') VALUES ('images/04-01-2015-14' at line 1

index.php:

<form action="saveimage.php" enctype="multipart/form-data" method="post">

<table style="border-collapse: collapse; font: 12px Tahoma;" border="1" cellspacing="5" cellpadding="5">
<tbody><tr>
<td>
<input name="uploadedimage" type="file">
</td>

</tr>

<tr>
<td>
<input name="Upload Now" type="submit" value="Upload Image">
</td>
</tr>

</tbody></table>

</form>

index2.php:

<?php
include("mysqlconnect.php");

$select_query = "SELECT 'images_path' FROM  'images_tbl' ORDER by 'images_id' DESC";
$sql = mysql_query($select_query) or die(mysql_error());    
while($row = mysql_fetch_array($sql,MYSQL_BOTH)){

?>

<table style="border-collapse: collapse; font: 12px Tahoma;" border="1" cellspacing="5" cellpadding="5">
<tbody><tr>
<td>

<img src="<?php echo $row[" images_path"];="" ?="">" alt="" />">

</td>
</tr>
</tbody></table>

<?php
}
?>

mysqlconnect.php:

<?php
/**********MYSQL Settings****************/
$host="localhost";
$databasename="karma";
$user="root";
$pass="";
/**********MYSQL Settings****************/

$conn=mysql_connect($host,$user,$pass);

if($conn)
{
$db_selected = mysql_select_db($databasename, $conn);
if (!$db_selected) {
    die ('Can\'t use foo : ' . mysql_error());
}
}
else
{
    die('Not connected : ' . mysql_error());
}
?>

saveimage.php:

<?php
include("mysqlconnect.php");

    function GetImageExtension($imagetype)
     {
       if(empty($imagetype)) return false;
       switch($imagetype)
       {
           case 'image/bmp': return '.bmp';
           case 'image/gif': return '.gif';
           case 'image/jpeg': return '.jpg';
           case 'image/png': return '.png';
           default: return false;
       }
     }

if (!empty($_FILES["uploadedimage"]["name"])) {

    $file_name=$_FILES["uploadedimage"]["name"];
    $temp_name=$_FILES["uploadedimage"]["tmp_name"];
    $imgtype=$_FILES["uploadedimage"]["type"];
    $ext= GetImageExtension($imgtype);
    $imagename=date("d-m-Y")."-".time().$ext;
    $target_path = "images/".$imagename;

if(move_uploaded_file($temp_name, $target_path)) {

    $query_upload="INSERT into 'images_tbl' ('images_path','submission_date') VALUES 

('".$target_path."','".date("Y-m-d")."')";
    mysql_query($query_upload) or die("error in $query_upload == ".mysql_error());  

}else{

   exit("Error While uploading image on the server");
} 

}

?>;

SQL:

CREATE TABLE images_tbl(
   images_id INT NOT NULL AUTO_INCREMENT,
   images_path VARCHAR(200) NOT NULL,
   submission_date DATE,
   PRIMARY KEY (images_id)
);

Answer 1

从 table name 和 column list 中删除 single quotes。

INSERT into images_tbl (images_path,submission_date) 
         VALUES ('images/04-01-2015-1420392279.png','2015-01-04')

如果 object 名称类似于 keywords 则使用 backticks 而不是 single quotes

Answer 2

不要将 'images_tbl' 和列名放在引号之间：正确的查询应该是

$query_upload="INSERT into images_tbl (images_path,submission_date) VALUES ('images/04-01-2015-1420392279.png','2015-01-04')

Answer 3

我认为您混淆了 back-ticks 与 single quotes ,

您应该将 MySQL 对象名称用反引号括起来，而不是用单引号引起来

INSERT into `images_tbl` (`images_path`,`submission_date`) 
VALUES ('images/04-01-2015-1420392279.png','2015-01-04')

由于 SQL 语法错误

Error because of SQL syntax

php

mysql