如何计算每一行的列数据总和？

Question

如何计算每一行中一列的总数？

这样，如果我有一个 Cost 列并且它的每一行都有数据，那么我想在最后计算它的总和, 按特定列分组并满足特定条件。

我试过：

SELECT
       [SchemeName]
      ,SUM(CAST([SchemeCost] as INT)) as COST
      ,[SchemeHolderName]
      ,[SchemeApprovedBy]
  FROM [WMS_MCP].[dbo].[Schemes]
  Where SchemeHolderName like '%'+ 'Hussain' +'%'
  Group By SchemeCost,SchemeName,SchemeHolderName,SchemeApprovedBy

  UNION ALL

  SELECT
       ''
      ,SUM(CAST([SchemeCost] as INT)) as COST
      ,''
      ,''
  FROM [WMS_MCP].[dbo].[Schemes]
  Where SchemeHolderName like '%'+ 'Hussain' +'%'
  Group By SchemeCost,SchemeName,SchemeHolderName,SchemeApprovedBy

但它没有产生所需的输出，我希望最后一行为空，其中只有 TOTALCOST。

Answer 1

从 union

中的第二个 select 语句中删除 Group by 子句

    SELECT
   [SchemeName]
  ,SUM(CAST([SchemeCost] as INT)) as COST
  ,[SchemeHolderName]
  ,[SchemeApprovedBy]
  FROM [WMS_MCP].[dbo].[Schemes]
  Where SchemeHolderName like '%'+ 'Hussain' +'%'
  Group By SchemeCost,SchemeName,SchemeHolderName,SchemeApprovedBy

  UNION ALL

  SELECT
   ''
  ,SUM(CAST([SchemeCost] as INT)) as COST
  ,''
  ,''
  FROM [WMS_MCP].[dbo].[Schemes]
  Where SchemeHolderName like '%'+ 'Hussain' +'%'

如何计算每一行的列数据总和？

How do I calculate sum of column data for each row ?

sql

sql-server

relational-database

sql-server-2008

sql-server-2012