正则表达式：将一些模式合并为一个

Question

我有一个包含以下内容的数据集：

(event) (tag) [group (artist)] title (form) [addition1] [addition2]
(event) [group (artist)] title (form) [addition1]
[event] [group (artist)] title (form) (addition1)
(tag) [group (artist)] title
[group (artist)] title
title
【tag】 [group (artist)] title 【form】
[group (artist)] title
[group] title
[artist] title
(artist) title

我想从每一行中获取标题。匹配标题的模式有3种：
1. ([\)\]】]\s*(?P<title>[^\(\)\[\]\【\】\s]*)\s*[\(\[【])

可以匹配某些行，例如 *] title (*

2。 ([\)\]】]\s*(?P<title>[^\(\)\[\]\【\】\s]*)
匹配像 *] title

这样的行

3。 (?P<title>[^\(\)\[\]\【\】\s]*)
匹配行只是 title

我不知道如何将三个规则组合成一个正则表达式。所以，我写了一些 Python 代码来做到这一点：

匹配模式1，突破，获得称号
不匹配模式 1，尝试匹配模式 2
循环步骤 1,2

我正在尝试将这三个规则合并为一个。

Answer 1

类似

(?:^|[])] +)(?P<title>\w+)(?: +[[【(]|$)

Regex demo

例子

>>> strings = ["(event) (tag) [group (artist)] title (form) [addition1] [addition2]", "(event) [group (artist)] title (form) [addition1]", "[event] [group (artist)] title (form) (addition1)", "(tag) [group (artist)] title", "[group (artist)] title", "title", "【tag 】 [group (artist)] title 【form】", "[group (artist)] title", "[group] title", "[artist] title", "(artist) title"]

>>> for string in strings:
...     re.findall(r'(?:^|[])] +)(?P<title>\w+)(?: +[[【(]|$)', string )                                                             ...
['title']
['title']
['title']
['title']
['title']
['title']
['title']
['title']
['title']
['title']
['title']

正则表达式：将一些模式合并为一个

Regex: merge some pattern into one

python

regex

extract