根据列字段删除重复项并修改它

Removing duplicates based on column field and modify it

假设我们有以下 List/IEnumerable

Program : CPE, ECE

旧列表:

Name            Assigned_Area    Program
Ivan Matala     Mathematics      CPE
Ivan Matala     Mathematics      ECE
Jeremy Cruz     Science          ECE
Ivan Matala     Science          CPE
NJ Aquino       Engineering      CPE
MJ Catanaoan    Engineering      ECE      

新列表:

Name            Assigned_Area    Program
Ivan Matala     Mathematics      All Programs
Jeremy Cruz     Science          ECE
Ivan Matala     Science          CPE
NJ Aquino       Engineering      CPE
MJ Catanaoan    Engineering      ECE    

基本上,我想做的是合并每条 'Name' 和 'Assigned_Area' 字段相同的记录,如果每条记录都有两个程序(在我们的例子中:'CPE' 和 'ECE'),那么它应该只是折叠成一行,其 Program 现在是 'All Programs'.

我们如何使用 LINQ 来实现?

到目前为止我试过的是以下不完整的代码

var newlist = oldlist.GroupBy(x => x.Assigned_Area);

基本上,我正在考虑将那些具有相同分配区域的记录分组,但是上面的代码是不完整的,因为它只考虑了一个字段(我需要考虑 2 个字段,它们是 'Name' 和 'Assigned_Area'),然后,如果每个分组的计数为 2,我将计数,如果它的计数为 2,那么我会将其折叠为一条记录,并将程序替换为 'All Programs' .


跟进问题但与上述问题有关..

以上问题适用于非匿名类。基本上,我真正的问题是,我有以下代码

  public IEnumerable GetOfficialList(int visitID)
        {
            db = new PACUCOADB5Entities();

            var x = (from a in db.Accreditor_Program
                     orderby a.Accreditor.Given_Name, a.Accreditor.Middle_Initial, a.Accreditor.Surname, a.Assigned_Area, a.Program.Requested_Program ascending
                     where a.Program.Visit.VisitID == visitID
                     select new
                     {
                         a.Accreditor.Title,
                         a.Accreditor.Given_Name,
                         a.Accreditor.Middle_Initial,
                         a.Accreditor.Surname,
                         a.Assigned_Area,
                         a.Program.Requested_Program
                     }).ToList();

         return x
     }

如您所见,'x' 是我的 list/IEnumerable,我正在尝试将相同的概念应用到我正在处理的代码中...基本上,我想做同样的事情,但是我尝试使用以下代码未成功

var newx = x.GroupBy(xx => new {xx.Title,xx.Given_Name,xx.Middle_Initial,xx.Surname,xx.Assigned_Area})
                .Select(xx => new {xx.Key.Title, xx.Key.Given_Name, xx.Key.Middle_Initial, xx.Key.Surname, xx.Key.Assigned_Area, xx.Count() == 2 ? "All Programs" :x.First(y => y.Title == xx.Key.Title && y.Given_Name == xx.Key.Given_Name && y.Middle_Initial == xx.Key.Middle_Initial && y.Surname == xx.Key.Surname && y.Assigned_Area == xx.Key.Assigned_Area).Requested_Program));

但 Intellisense 通过我的错误

我们如何解决它?给定该代码,我们如何删除重复项。谢谢

可能有更好的方法,但这是我的尝试:

Person[] r = list.GroupBy(p => new { p.Name, p.AssignedArea })
                 .Select(g => g.ToArray())
                 .Select(g => g.Length > 1
                              UpdateProgram(g.First()) :
                              g.First())
                 .ToArray();

private static Person UpdateProgram(Person p)
{
    p.Program = "All Programs";
    return p;       
}

但就我个人而言,我会使用分组表达式和常规 foreach 循环:

foreach (var g in list.GroupBy(p => new { p.Name, p.AssignedArea }))
{
    var p = g.First();
    if (g.Count() > 1)
    {
        p.Program = "All Programs";
    }
    yield return p;
}
oldList.GroupBy(x => new { x.Name, x.AssignedArea })
       .Select(g => g.Count() == 1
           ? new Entity(g.Key.Name, g.Key.AssignedArea, g.Single().Program)
           : new Entity(g.Key.Name, g.Key.AssignedArea, "All programs")
       );

此处 Entity 是您的 class,其中包含 NameAssignedAreaProgram 字段(您的代码中没有它的名称)。所有这些都将假设程序的数量可能是 1 或 2

这会起作用:

var result = v.GroupBy(x => new { x.Name, x.Assigned_Area})
              .Select(x => new EntityName(x.Key.Name, 
                                          x.Key.Assigned_Area, 
                                          x.Count() == 2 ? "All Programs" :v.First(y => y.Name == x.Key.Name && y.Assigned_Area== x.Key.Assigned_Area).Program) );

Demo

我从字面上接受了 Mark Shevchenko 的答案并更新了考虑具有相同名称、AsisgnedArea 和程序的多行:

list
.GroupBy(x => new { x.Name, x.Area })
.Select(g =>
    g.Select(x=>x.Programs).Distinct().Count() == 1 ?
    new Data {Name=g.Key.Name, Area=g.Key.Area, Programs=g.First().Programs} :
    new Data {Name=g.Key.Name, Area=g.Key.Area, Programs="All programs"});

您可以使用以下方法进行测试:

public struct Data
{
    public string Name;
    public string Area;
    public String Programs;
}

void Main()
{
    var list= new List<Data>()
    { 
        new Data(){ Name="Ivan Matala", Area = "Mathematics", Programs = "CPE" },
        new Data(){ Name="Ivan Matala", Area = "Mathematics", Programs = "ECE" },
        new Data(){ Name="Jeremy Cruz", Area = "Science", Programs = "ECE" },
        new Data(){ Name="Ivan Matala", Area = "Science", Programs = "CPE" },
        new Data(){ Name="NJ Aquino", Area = "Engineering", Programs = "CPE" },
        new Data(){ Name="MJ Catanaoan", Area = "Engineering", Programs = "ECE" },
        new Data(){ Name="MJ Catanaoan", Area = "Science", Programs = "CPE" },
        new Data(){ Name="MJ Catanaoan", Area = "Science", Programs = "CPE" }
    };
}