计算日期之间的特定工作日并排除 Javascript 中的假期

Question

从 this question 开始，它使用以下方法计算给定日期范围内特定工作日的数量：

function countCertainDays( days, d0, d1 ) {
  var ndays = 1 + Math.round((d1-d0)/(24*3600*1000));
  var sum = function(a,b) {
      return a + Math.floor( ( ndays + (d0.getDay()+6-b) % 7 ) / 7 );
  };
  return days.reduce(sum,0);
}

我还想知道如果假期落在范围内的工作日，如何排除假期，假设我有一系列假期发生在 d0 和 d1 之间。

感谢帮助！

Answer 1

前段时间我写了类似的脚本也许对你有帮助：

var today = new Date();
var end = new Date(2016, 6, 1);
var allDays = Math.floor((end.getTime() - today.getTime())/ 86400000);
var holidays = [
    [15, 8],[1, 10],[17, 10],[29,9],[30,9],[23,11],[24,11],[25,11],[26,11],[27,11],[28,11],[29,11],[30,11],[31,11],[1,0],[2,0], [3,0],[4,0],[5,0],[6,0],[7,0],[1,1],[31,0],[22,1],[23,1],[24,1],[25,1],[26,1],[24,2],[25,2],[26,2],[27,2],[28,2],[29,2],[1,4],[8,4],
    ];

var days = 0;
    for(var i = 0; i < allDays; i++){
    var tmpDate = new Date();
    tmpDate.setTime(today.getTime() + i * 24*60*60*1000);
    var bool = true;
    for(var j = 0; j < holidays.length; j++){
        if( tmpDate.getDate() == holidays[j][0] && tmpDate.getMonth() == holidays[j][1] )
            bool = false;
    }
    if(tmpDate.getDay() != 0 && tmpDate.getDay() != 6 && bool)
        days++;
}
console.log(days);

Answer 2

我最终计算了工作日的假期数量，然后将其与原始函数产生的结果进行差分。这具有允许我打开或关闭计算的额外优势。

var holidays=[x,y,z] 
//where x,y and z are weekday numbers falling in the date range (obtained using something like .isBetween)
var desired_weekdays=[a,b]

var falling_on_weekdays= function(holidays,desired_weekdays){
    for (var i=0; i < holidays.length; i++) {
        if ($.inArray(holidays[i],desired_weekdays)==0){
            count++}
        }
    }
};

然后：

if($('.#checkbox').prop("checked")===true){
            return days.reduce(sum,0);              
        }
        else {
            return days.reduce(sum,0)-falling_on_weekdays;
        }

计算日期之间的特定工作日并排除 Javascript 中的假期

Calculate specific weekdays between dates and exclude holidays in Javascript

javascript

momentjs