具有级别详细信息的用户树视图结构
users treeview structure with level details
我正在尝试创建用户的树视图结构,每个用户将有 2 个子节点,我的代码完美地创建了树视图,但我坚持获取级别信息。
public function treeView() {
$this->load->view('header');
$leftArray=array('viewMode'=>'admin',"isLogin"=>$this->session->userdata('isUserLogin'));
$this->load->view('left',$leftArray);
$alias="*";
$table="user";
$where=array("userId"=>$this->session->userdata('userId'));
$userDetails= $this->commonmodel->getData($alias,$table,$where);
$this->getTreeArray($userDetails[0]->userId, $this->stageCounter);
$treeArray = json_encode($this->globTreeArray);
//echo $this->stageCounter;exit;
//echo "<pre>";
//print_r($this->globTreeArray);
//exit;
$treeviewArray=array("treeArray"=>$treeArray,"userDetails"=>$userDetails[0]);
$this->load->view('treeView',$treeviewArray);
$this->load->view('footer');
}
public function getTreeArray($userId,$level) {
$childArray=array();
$alias="*";
$table="user_relationship";
$where=array("placementUserId"=>$userId);
$childRecords= $this->commonmodel->getData($alias,$table,$where);
foreach ($childRecords as $child){
$temp=array();
if($child->placementSide=='left'){
$childUserDetails=$this->getUserDetails($child->childUserId);
$temp[]="<div><img src='". base_url()."assets/img/default-avatar.png' width='80'/></div>".$childUserDetails->registrationCode."</br>".$childUserDetails->fullName;
$placementUserDetails=$this->getUserDetails($child->placementUserId);
$temp[]="<div><img src='". base_url()."assets/img/default-avatar.png' width='80'/></div>".$placementUserDetails->registrationCode."</br>".$placementUserDetails->fullName;
$temp[]=(string)$this->stageCounter;
$childArray[0]=$temp;
$this->globTreeArray[]=$temp;
}
if($child->placementSide=='right'){
$childUserDetails=$this->getUserDetails($child->childUserId);
$temp[]="<div><img src='". base_url()."assets/img/default-avatar.png' width='80'/></div>".$childUserDetails->registrationCode."</br>".$childUserDetails->fullName;
$placementUserDetails=$this->getUserDetails($child->placementUserId);
$temp[]="<div><img src='". base_url()."assets/img/default-avatar.png' width='80'/></div>".$placementUserDetails->registrationCode."</br>".$placementUserDetails->fullName;
$temp[]=(string)$this->stageCounter;
$childArray[1]=$temp;
$this->globTreeArray[]=$temp;
}
//if($level<=2)
//{
//echo $level."------".$childUserDetails->registrationCode."----------".$placementUserDetails->registrationCode."<br>";
if($this->hasChildren($childUserDetails->userId)==TRUE)
{
$this->stageCounter++;
$this->getTreeArray($childUserDetails->userId,$this->stageCounter);
}
else
{
$this->stageCounter--;
}
//}
}
//echo "<pre>";
//print_r($this->globTreeArray);
//exit;
return json_encode($this->globTreeArray);
}
如我的代码所示,我需要三个元素在 0 位置子级、1 位置父级和 2 位置级别编号,
您可以按照以下步骤实现您的目标
1) 拿一个全局数组说 $Leveldata = array()
2) 每次你调用该函数时都有 child,如果你发现 child 将该数据推入数组
3) 一旦你得到了你想要的等级数的计数器,比如 3,
打破循环
希望这个建议对你有帮助,你可以继续
谢谢
我正在尝试创建用户的树视图结构,每个用户将有 2 个子节点,我的代码完美地创建了树视图,但我坚持获取级别信息。
public function treeView() {
$this->load->view('header');
$leftArray=array('viewMode'=>'admin',"isLogin"=>$this->session->userdata('isUserLogin'));
$this->load->view('left',$leftArray);
$alias="*";
$table="user";
$where=array("userId"=>$this->session->userdata('userId'));
$userDetails= $this->commonmodel->getData($alias,$table,$where);
$this->getTreeArray($userDetails[0]->userId, $this->stageCounter);
$treeArray = json_encode($this->globTreeArray);
//echo $this->stageCounter;exit;
//echo "<pre>";
//print_r($this->globTreeArray);
//exit;
$treeviewArray=array("treeArray"=>$treeArray,"userDetails"=>$userDetails[0]);
$this->load->view('treeView',$treeviewArray);
$this->load->view('footer');
}
public function getTreeArray($userId,$level) {
$childArray=array();
$alias="*";
$table="user_relationship";
$where=array("placementUserId"=>$userId);
$childRecords= $this->commonmodel->getData($alias,$table,$where);
foreach ($childRecords as $child){
$temp=array();
if($child->placementSide=='left'){
$childUserDetails=$this->getUserDetails($child->childUserId);
$temp[]="<div><img src='". base_url()."assets/img/default-avatar.png' width='80'/></div>".$childUserDetails->registrationCode."</br>".$childUserDetails->fullName;
$placementUserDetails=$this->getUserDetails($child->placementUserId);
$temp[]="<div><img src='". base_url()."assets/img/default-avatar.png' width='80'/></div>".$placementUserDetails->registrationCode."</br>".$placementUserDetails->fullName;
$temp[]=(string)$this->stageCounter;
$childArray[0]=$temp;
$this->globTreeArray[]=$temp;
}
if($child->placementSide=='right'){
$childUserDetails=$this->getUserDetails($child->childUserId);
$temp[]="<div><img src='". base_url()."assets/img/default-avatar.png' width='80'/></div>".$childUserDetails->registrationCode."</br>".$childUserDetails->fullName;
$placementUserDetails=$this->getUserDetails($child->placementUserId);
$temp[]="<div><img src='". base_url()."assets/img/default-avatar.png' width='80'/></div>".$placementUserDetails->registrationCode."</br>".$placementUserDetails->fullName;
$temp[]=(string)$this->stageCounter;
$childArray[1]=$temp;
$this->globTreeArray[]=$temp;
}
//if($level<=2)
//{
//echo $level."------".$childUserDetails->registrationCode."----------".$placementUserDetails->registrationCode."<br>";
if($this->hasChildren($childUserDetails->userId)==TRUE)
{
$this->stageCounter++;
$this->getTreeArray($childUserDetails->userId,$this->stageCounter);
}
else
{
$this->stageCounter--;
}
//}
}
//echo "<pre>";
//print_r($this->globTreeArray);
//exit;
return json_encode($this->globTreeArray);
}
如我的代码所示,我需要三个元素在 0 位置子级、1 位置父级和 2 位置级别编号,
您可以按照以下步骤实现您的目标
1) 拿一个全局数组说 $Leveldata = array()
2) 每次你调用该函数时都有 child,如果你发现 child 将该数据推入数组
3) 一旦你得到了你想要的等级数的计数器,比如 3, 打破循环
希望这个建议对你有帮助,你可以继续
谢谢