subscribeOn 新线程有时不返回

Question

任何人都可以看看下面的代码，让我知道为什么它的行为不同：

package com.example.rxjava;

import rx.Observable;
import rx.functions.Action1;
import rx.schedulers.Schedulers;

public class MyRxJava {
    public static void main(String[] args) {
        System.out.println("getting sum ... by thread: " +
            Thread.currentThread().getId());
    //        observeOnNewThread();

    subOnNewThread();
    independentProcess();
    }

    private static void observeOnNewThread() {
        Observable.create(new CountObservable(100)).observeOn(Schedulers.newThread()).subscribe(new Action1<Integer>() {
            @Override
            public void call(Integer a) {
                System.out.println("processing dependent process " + a + "  ..... by thread: "+ Thread.currentThread().getId());
            }
        });
    }

    private static void subOnNewThread() {
        Observable.create(new CountObservable(100)).subscribeOn(Schedulers.newThread()).subscribe(new Action1<Integer>() {
            @Override
            public void call(Integer a) {
                System.out.println("processing dependent process " + a + "  ..... by thread: " + Thread.currentThread().getId());
            }
        });
    }

    private static void independentProcess() {
        System.out.println("precessing something else .... by thread: "+ Thread.currentThread().getId());
    }
}

package com.example.rxjava;

import rx.Observable;
import rx.Subscriber;

public class CountObservable implements Observable.OnSubscribe<Integer> {

private int value;

public CountObservable(int value) {
    this.value = value;
}

@Override
public void call(Subscriber<? super Integer> subscriber) {
    System.out.println("calculating sum ....  by thread: "+ Thread.currentThread().getId());

    int tot = 0;

    for (int k = 0; k<=value; k++) {
        try {
            Thread.sleep(10);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        tot+=k;
    }



        subscriber.onNext(tot);
        subscriber.onCompleted();
  }
}

有时会打印

getting sum ... by thread: 1
precessing something else .... by thread: 1

有时

getting sum ... by thread: 1
precessing something else .... by thread: 1
calculating sum ....  by thread: 11

无论如何，它不会在

中打印消息

@Override
public void call(Integer a) { ... }

方法

当我运行 observeOnNewThread() 方法有效时，但我想在不同的线程中计算总和

Answer 1

RxJava 调度程序运行在守护线程上，您的主要方法在它们有机会运行完成之前完成。您必须以某种方式等待它们：通过在 main 中休眠，通过使用 toBlocking().forEach() 或其他 toBlocking() 方法。

subscribeOn 新线程有时不返回

subscribeOn new thread sometimes not returning

java

multithreading

rx-java